Submission #1089188

#TimeUsernameProblemLanguageResultExecution timeMemory
1089188vjudge1Kpart (eJOI21_kpart)C++17
0 / 100
58 ms1116 KiB
//#pragma GCC optimize ("O3") //#pragma GCC target ("sse4") #include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace __gnu_pbds; #define ll long long #define ld long double #define ull unsigned long long #define pb push_back #define pob pop_back #define int long long #define int2 __int128_t #define Shrek_Crush228 ios_base::sync_with_stdio(0), cin.tie(0); #define F first #define S second #define FOR( i, x, n, d ) for( int i = x; i <= n; i += d ) #define FORR( i, x, n, d ) for( int i = x; i >= n; i -= d ) #define lb lower_bound #define ub upper_bound #define all(x) x.begin(), x.end() #define no cout << "NO\n" #define yes cout << "YES\n" #define nep next_permutation #define sigma signed #define pii pair <int, int> using namespace std; string alp = "abcdefghijklmnopqrstuvwxyz"; string ae = "aoeiuy"; string nums = "123456789"; const int N = 1e5 + 123; const int inf = 1e18; const int MOD = 1e9 + 7; const int MOD1 = 998244353; const long long maxsum = 1e14; int a[N], b[N], c[N], l, r, n, k, m, w, sum, sum1, y, ans1, mx = -inf, mn = inf, ind, ind1, pref[N], suf[N]; string s, s1; ll ans, x; template<class T> using ordered_multiset = tree<T, null_type, less_equal<T>, rb_tree_tag, tree_order_statistics_node_update>; struct RT { int sum, l, r, ind; }; int gcd( int a, int b ) { return ( b ? gcd( b, a % b ) : a ); } int lcm( int a, int b ) { return a / gcd( a, b ) * b; } int bp( int a, int b, int m ) { if( !b ) return 1; if( b & 1 ) return bp( a, b >> 1, m ) * bp( a, b >> 1, m ) % m * a % m; else return bp( a, b >> 1, m ) * bp( a, b >> 1, m ) % m; } struct po { int mn, sum, mx; }; int maxstart[N]; void solve() { cin >> n; x = pref[0] = 0; set <int> st; FOR( i, 1, n, 1 ) { cin >> a[i], x += a[i], st.insert( i ), pref[i] = pref[i - 1] + a[i]; } // base maxstart[0] = 0; FOR( i, 1, 100000, 1 ) maxstart[i] = -1; st.erase( 1 ); FOR( i, 1, n, 1 ) { maxstart[a[i]] = i; FORR( j, x, a[i], 1 ) maxstart[j] = max( maxstart[j], maxstart[j - a[i]] ); FOR( l, 1, i - 1, 1 ) { int len = i - l + 1; if( ( pref[i] - pref[l - 1] ) % 2 || l > maxstart[( pref[i] - pref[l - 1] ) >> 1] ) st.erase( len ); } } cout << st.size() << ' '; for( auto i : st ) cout << i << ' '; cout << '\n'; } sigma main() { //freopen("rmq.in", "r", stdin); //freopen("rmq.out", "w", stdout); Shrek_Crush228 int test = 0; if( !test ) cin >> test; while( test -- ) { solve(); } } // solved by KluydQ
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