Submission #1088434

#	Time	Username	Problem	Language	Result	Execution time	Memory
1088434		rlx0090	Split the sequence (APIO14_sequence)	C++14	0 / 100	101 ms	16176 KiB

sequence

#include <iostream>
#include <string>
#include <vector>
#include <algorithm>
#include <cmath>
#include <limits>
#include <queue>
#include <string.h>
#include <stack>
#include <limits>
 
using namespace std;
int N, K;
int cache[205][100005], p[100005];
long long dp[2][100005];
long long minf = numeric_limits<long long>::min();
struct seg {
    long long k = 0, b = minf;
    int label = 987654321;
    seg() {}
    seg(long long _k, long long _b, int _label) :k(_k), b(_b), label(_label) {}
    long long f(long long x) {
        return k * x + b;
    }
};
bool which_is_big(seg a, seg b, int x) {
    long long l = a.f(x), r = b.f(x);
   // cout << "l : " << l << " r : " << r << endl;
    if(l == r) return a.label < b.label;
    return l > r;
}
 
struct Node {
    seg s;
    int l = -1, r = -1;
    Node() {}
};
int pv = 1;
Node tree[400005];
Node null_Node;
void add(int n, seg ns, int nl = 0, int nr = 1e9) {
    int m = (nl + nr) / 2;
    bool lef = which_is_big(ns, tree[n].s, nl);
    bool mid = which_is_big(ns, tree[n].s, m);
    //cout << "before .." << endl;
    //cout << tree[n].s.f(m) << ", " << ns.f(m) << endl;
    if(mid) swap(tree[n].s, ns);
    //cout << "after .." << endl;
    //cout << tree[n].s.f(m) << ", " << ns.f(m) << endl;
    if(ns.b == minf) return;
    if(nl == nr) return;
    else if(lef != mid) {
        if(tree[n].l == -1) tree[n].l = pv++;
        add(tree[n].l, ns, nl, m);
    }
    else {
        if(tree[n].r == -1) tree[n].r = pv++;
        add(tree[n].r, ns, m + 1, nr);
    }
}
 
seg query(int n, int x, int nl = 0, int nr = 1e9) {
    if(n == -1) return seg();
    if(nl == nr) return tree[n].s;
    int m = (nl + nr) / 2;
    if(x <= m){
        seg c = query(tree[n].l, x, nl, m);
        //cout << "q......................" << endl;
        if(which_is_big(c, tree[n].s, x)) {
            //cout << "ret : " << c.f(x) << endl;
            return c;}
        {//cout << "ret : " << tree[n].s.f(x) << endl;
        return tree[n].s;}
    }
    else {
        seg c = query(tree[n].r, x, m + 1, nr);
        //cout << "q......................" << endl;
        if(which_is_big(c, tree[n].s, x)) {
            //cout << "ret : " << c.f(x) << endl; 
            return c;}
        {//cout << "ret : " << tree[n].s.f(x) << endl; 
        return tree[n].s;}
    }
}
 
int main() {
    ios::sync_with_stdio(false);
    cin.tie(NULL);
    cout.tie(NULL);
    cin >> N >> K;
    //N = 3;
    //K = 2;
    long long q;
    for(int i = 1; i <= N; ++i) {
        cin >> q;
        //q = 1000;
        p[i] = p[i - 1] + q;
    }
    int before = 0, cur = 0;
    for(int k = 1; k <= K; ++k) {
        before = k % 2; cur = (k + 1) % 2;
        for(int i = N;  i >= 0; --i) {
            add(0, seg(p[i + 1], - p[i + 1] * p[i + 1] + p[N] * p[i + 1] + dp[before][i + 1], i + 1));
            seg c = query(0, p[i]);
            dp[cur][i] = c.f(p[i]) - p[N] * p[i];
            //cout << "cand : " << dp[cur][i] << endl;
            cache[k][i] = c.label;
        }
        for(int i = 0; i <= 4 * N; ++i)
            tree[i] = null_Node;
        pv = 1;
    }
    cout << dp[cur][0] << '\n';
    int s = 0;
 
    for(int k = K; k >= 1; --k) {
        cout << cache[k][s] << ' ';
        s = cache[k][s];
    }
 
    return 0;
}

• Subtask 1: 0 / 11
• Subtask 2: 0 / 11
• Subtask 3: 0 / 11
• Subtask 4: 0 / 17
• Subtask 5: 0 / 21
• Subtask 6: 0 / 29