Submission #1088335

#	Time	Username	Problem	Language	Result	Execution time	Memory
1088335		browntoad	Boxes with souvenirs (IOI15_boxes)	C++14	35 / 100	1 ms	432 KiB

boxes

#include <bits/stdc++.h>
#include "boxes.h"
using namespace std;
#define ll long long
// #define int ll
#define FOR(i, a, b) for (int i = (a); i < (b); i++)
#define REP(i, n) FOR(i, 0, n)
#define REP1(i, n) FOR(i, 1, n+1)
#define RREP(i, n) for (int i = (n)-1; i >= 0; i--)
#define pii pair<int, int>
#define f first
#define s second
#define pb push_back
#define ALL(x) (x).begin(), (x).end()
#define SZ(x) (int)((x).size())
 
const ll maxn = 1e5+5;
 
ll delivery(int n, int k, int len, int pos[]){
    vector<int> vc(n);
    REP(i, n){
        vc[i] = pos[i];
    }
    sort(ALL(vc));
    if (k == 1){
        ll ans = 0;
        REP(i, n){
            ans += min(pos[i], len-pos[i]);
        }
        return ans*2;
    }
 
    ll ans = 0;
    vector<int> L, R;
    vector<ll> lmod(k), rmod(k);
    REP(i, n){
        if (vc[i] < len-vc[i]) {
            L.pb(vc[i]);
        }
        else {
            R.pb(len-vc[i]);
        }
    }
    sort(ALL(L), greater<int> ()); sort(ALL(R), greater<int> ());
 
    if (SZ(L) > SZ(R)) swap(L, R);
    for (int i = 0; i < SZ(L); i += k) ans += L[i];
    for (int i = 0; i < SZ(R); i += k) ans += R[i];
    ans *= 2;
 
    if (SZ(L) + SZ(R) <= k) return min((ll)(len), ans);
 
    int l = min(SZ(L), k);
    int r = k-l;
    FOR(i, l, SZ(L)){
        lmod[i%k] += 2*L[i];
    }
    FOR(i, r, SZ(R)){
        rmod[i%k] += 2*R[i];
    }
 
    while(l >= 0 && r <= SZ(R)){
        ll cur = len;
        if (l != SZ(L)) cur += lmod[l%k];
        if (r != SZ(R)) cur += rmod[r%k];
        ans = min(ans, cur);
 
        if (l == 0 || r == 0){
            break;
        }
 		l--;
        lmod[l%k] += 2*L[l];
        rmod[r%k] -= 2*R[r];
      	r++;
    }
    return ans;
}

• Subtask 1: 10 / 10
• Subtask 2: 10 / 10
• Subtask 3: 15 / 15
• Subtask 4: 0 / 15
• Subtask 5: 0 / 20
• Subtask 6: 0 / 30