Submission #1087332

#	Time	Username	Problem	Language	Result	Execution time	Memory
1087332		vladilius	Diversity (CEOI21_diversity)	C++17	64 / 100	7024 ms	11736 KiB

diversity

#include <bits/stdc++.h>
#pragma GCC optimize("O3,unroll-loops")
#pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")
using namespace std;
using ll = long long;
using pii = pair<int, int>;
#define pb push_back
#define ff first
#define ss second
#define ins insert
#define arr3 array<int, 3>
const int A = 3e5;

struct FT{
    ll bit[A + 1];
    int n;
    FT(int ns){
        n = ns;
        for (int i = 1; i <= n; i++){
            bit[i] = 0;
        }
    }
    void upd(int v, ll x){
        while (v <= n){
            bit[v] += x;
            v |= (v + 1);
        }
    }
    ll get(int v){
        ll out = 0;
        while (v > 0){
            out += bit[v];
            v = (v & (v + 1)) - 1;
        }
        return out;
    }
    ll get(int l, int r){
        if (l > r) return 0;
        return get(r) - get(l - 1);
    }
};

int main(){
    ios_base::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);
    
    int n, q; cin>>n>>q;
    vector<int> a(n + 1);
    for (int i = 1; i <= n; i++){
        cin>>a[i];
    }
    
    vector<arr3> qs;
    for (int i = 1; i <= q; i++){
        int l, r; cin>>l>>r;
        qs.pb({l, r, i});
    }
    
    const int S = sqrt(n);
    auto cmp = [&](arr3 x, arr3 y){
        if (x[0] / S == y[0] / S){
            return x[1] < y[1];
        }
        return x[0] < y[0];
    };
    sort(qs.begin(), qs.end(), cmp);
    
    vector<int> p(n + 1);
    for (int i = 1; i <= n; i++){
        if (i % 2){
            p[i] = (i + 1) / 2;
        }
        else {
            p[i] = n - i / 2 + 1;
        }
    }
    
    ll sum = 0;
    vector<int> f(n + 1), cnt(A + 1);
    vector<int> :: iterator it;
    FT T1(n), T2(n);
    auto add = [&](int x){
        x = a[x];
        it = upper_bound(f.begin() + 1, f.end(), cnt[x]); it--;
        int j1 = (int) (it - f.begin()), j = p[j1];
        
        sum += (f[j1] + 1);
        sum += (1LL * j * T1.get(1, j - 1));
        sum -= (T2.get(1, j - 1) - T1.get(1, j - 1));
        sum += T2.get(j + 1, n);
        sum -= 1LL * (j - 1) * T1.get(j + 1, n);
        
        cnt[x]++; f[j1]++;
        T1.upd(j, 1);
        T2.upd(j, j);
    };

    auto rem = [&](int x){
        x = a[x];
        it = lower_bound(f.begin() + 1, f.end(), cnt[x]);
        int j1 = (int) (it - f.begin()), j = p[j1];
        
        sum -= f[j1];
        sum -= (1LL * j * T1.get(1, j - 1));
        sum += (T2.get(1, j - 1) - T1.get(1, j - 1));
        sum -= T2.get(j + 1, n);
        sum += 1LL * (j - 1) * T1.get(j + 1, n);
        
        cnt[x]--; f[j1]--;
        T1.upd(j, -1);
        T2.upd(j, -j);
    };
    
    vector<ll> out(q + 1);
    int lc = 1, rc = 0;
    for (auto [l, r, ii]: qs){
        while (lc < l) rem(lc++);
        while (lc > l) add(--lc);
        while (rc < r) add(++rc);
        while (rc > r) rem(rc--);
        
        out[ii] = sum;
    }
    
    for (int i = 1; i <= q; i++){
        cout<<out[i]<<"\n";
    }
}

• Subtask 1: 4 / 4
• Subtask 2: 10 / 10
• Subtask 3: 8 / 8
• Subtask 4: 16 / 16
• Subtask 5: 26 / 26
• Subtask 6: 0 / 36