Submission #1087229

#TimeUsernameProblemLanguageResultExecution timeMemory
1087229mispertionBoat (APIO16_boat)C++14
31 / 100
815 ms40276 KiB
#include <bits/stdc++.h> using namespace std; #pragma GCC optimize("Ofast") #pragma GCC optimize("O3") #pragma GCC optimize("unroll-loops") mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); typedef long long ll; #define int ll typedef unsigned long long ull; typedef long double ld; typedef pair<int, int> pii; typedef pair<ll, ll> pll; #define pb push_back #define all(x) x.begin(), x.end() #define sz(x) (int)x.size() #define mispertion ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0) #define F first #define S second #define getlast(s) (*s.rbegin()) #define debg cout << "OK\n" const ld PI = 3.1415926535; const int N = 5e5 + 10; const int M = 1e5 + 10; int mod = 1e9+7; const int infi = INT_MAX; const ll infl = 2e18; const int P = 505319; const ld eps = 1e-9; int mult(int a, int b){ return a * 1LL * b % mod; } int sum(int a, int b){ a %= mod; b %= mod; if(a + b >= mod) return a + b - mod; if(a + b < 0) return a + b + mod; return a + b; } int binpow(int a, int n){ if (n == 0) return 1; if (n % 2 == 1){ return mult(binpow(a, n - 1), a); } else{ auto b = binpow(a, n / 2); return mult(b, b); } } int n, l[N], r[N], sm[N], f[N], fi[N]; vector<int> al[N]; int C(int n, int k){ return mult(f[n], mult(fi[k], fi[n - k])); } void solve(){ cin >> n; vector<int> di = {}; for(int i = 1; i <= n; i++){ cin >> l[i] >> r[i]; di.pb(l[i]); di.pb(r[i] + 1); } di.pb(0); sort(all(di)); di.resize(unique(all(di)) - di.begin()); sm[0] = 1; al[0].pb(1); for(int i = 1; i <= n; i++){ int cur = 0; for(int j = 0; j < sz(di) - 1; j++){ int lr = di[j], rr = di[j + 1] - 1; int len = rr - lr + 1; if(lr >= l[i] && rr <= r[i]){ al[j].pb(cur); int nsm = 0; for(int k = 0; k < sz(al[j]); k++){ nsm =sum(nsm, mult(C(sz(al[j]) - k - 1 + len, sz(al[j]) - k), al[j][k])); } cur = sum(cur, sm[j]); sm[j] = nsm; }else{ cur = sum(cur, sm[j]); } } } int ans = 0; for(int i = 0; i < sz(di) - 1; i++) ans = sum(ans, sm[i]); cout << sum(ans, -1) << '\n'; } signed main(){ mispertion; f[0] = 1; for(int i = 1; i < N; i++) f[i] = mult(f[i - 1], i); for(int i = 0; i < N; i++){ fi[i] = binpow(f[i], mod - 2); } int t = 1; //cin >> t; while (t--){ solve(); } return 0; }
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