Submission #1086867

#	Time	Username	Problem	Language	Result	Execution time	Memory
1086867		alexdumitru	Abracadabra (CEOI22_abracadabra)	C++17	0 / 100	1 ms	856 KiB

Main

#include <iostream>
#include <vector>
#include <stack>
#include <set>
#include <map>
#include <algorithm>

using namespace std;

const int NMAX = 100;
const int QMAX = 100;

int n, q;
int a[NMAX + 2];
pair<int, int> qr[QMAX + 1];
int ans[QMAX + 1];
vector<int> idQ[NMAX + 1];
int nxt[NMAX + 2];

void read() {
    cin >> n >> q;
    for (int i = 1; i <= n; i++)
        cin >> a[i];
    a[n + 1] = n + 1;
    for (int i = 1; i <= q; i++) {
        cin >> qr[i].first >> qr[i].second;
        qr[i].first = min(qr[i].first, n - 1);
        idQ[qr[i].first].push_back(i);
    }
}

struct Block {
    int v, l, r;
    bool operator < (const Block & oth) const {
        return v < oth.v;
    }
};

set<Block> s;
vector<Block> vtot;
map<Block, int> mp;

namespace AIB {
    int aib[2 * NMAX + 1];
    int m = 2 * n;

    int query(int pos) {
        int res = 0;
        for (; pos > 0; pos -= pos & -pos)
            res += aib[pos];
        return res;
    }

    void update(int pos, int v) {
        for (; pos <= m; pos += pos & -pos)
            aib[pos] += v;
    }

    int get_block(int pos) {
        int idx = 0, s = 0;
        for (int b = 18; b >= 0; b--) {
            if (idx + (1 << b) <= m && s + aib[idx + (1 << b)] < pos) {
                s += aib[idx + (1 << b)];
                idx += (1 << b);
            }
        }
        return idx + 1;
    }

    void init(int _m) {
        m = _m;
    }
}

void adauga(Block b) {
    s.insert(b);
    AIB::update(mp[b], + (b.r - b.l + 1));
}

void scoate(Block b) {
    s.erase(b);
    AIB::update(mp[b], - (b.r - b.l + 1));
}

void solve() {
    stack<int> stk;
    stk.push(n + 1);
    for (int i = n; i >= 1; i--) {
        while (a[stk.top()] < a[i]) stk.pop();
        nxt[i] = stk.top();
        stk.push(i);
    }

    for (int st = 1; st <= n; st = nxt[st]) {
        s.insert({a[st], st, nxt[st] - 1});
        vtot.push_back({a[st], st, nxt[st] - 1});
    }

    int ltotal = n;

    for (int step = 0; step <= n - 1; step++) {
        while (true) {
            auto it = prev(s.end());
            if (ltotal - (it->r - it->l) > n / 2) {
                ltotal -= (it->r - it->l + 1);
                s.erase(it);
            } else break;
        }

        if (ltotal > n / 2) {
            auto ult = prev(s.end());
            int L = ult->l, R = ult->r, V = ult->v;
            s.erase(ult);

            int lgR = ltotal - n / 2;
            int lgL = R - L + 1 - lgR;

            int v1 = V;
            int l1 = L;
            int r1 = L + lgL - 1;
            s.insert({v1, l1, r1});
            vtot.push_back({v1, l1, r1});

            int l2 = r1 + 1;
            int r2 = l2 + lgR - 1;

            for (int idx = l2; idx <= r2; idx = nxt[idx]) {
                s.insert({a[idx], idx, nxt[idx] - 1});
                vtot.push_back({a[idx], idx, nxt[idx] - 1});
            }
        }
    }

    sort(vtot.begin(), vtot.end());

    int cnt = vtot.size();

    for (int i = 0; i < cnt; i++) {
        mp[vtot[i]] = i + 1;
    }

    s.clear();
    ltotal = n;

    AIB::init(cnt);

    for (int st = 1; st <= n; st = nxt[st]) {
        adauga({a[st], st, nxt[st] - 1});
    }

    ltotal = n;

    for (int step = 0; step <= n - 1; step++) {
        for (int idxQ : idQ[step]) {
            int pos = qr[idxQ].second;
            int t = AIB::get_block(pos);
            ans[idxQ] = a[vtot[t - 1].l + pos - AIB::query(t - 1) - 1];
        }

        while (true) {
            auto it = prev(s.end());
            if (ltotal - (it->r - it->l) > n / 2) {
                ltotal -= (it->r - it->l + 1);
                s.erase(*it);
                //scoate(*it);
            } else break;
        }

        if (ltotal > n / 2) {
            auto ult = prev(s.end());
            int L = ult->l, R = ult->r, V = ult->v;
            scoate(*ult);

            int lgR = ltotal - n / 2;
            int lgL = R - L + 1 - lgR;

            int v1 = V;
            int l1 = L;
            int r1 = L + lgL - 1;
            adauga({v1, l1, r1});

            int l2 = r1 + 1;
            int r2 = l2 + lgR - 1;


            for (int idx = l2; idx <= r2; idx = nxt[idx]) {
                adauga({a[idx], idx, nxt[idx] - 1});
            }
        }
    }
}

void write() {
    for (int i = 1; i <= q; i++) {
        cout << ans[i] << '\n';
    }
}

int main() {
    ios_base::sync_with_stdio(false);
    cin.tie(nullptr);
    read();
    solve();
    write();
    return 0;
}

• Subtask 1: 0 / 10
• Subtask 2: 0 / 40
• Subtask 3: 0 / 25
• Subtask 4: 0 / 25