This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
using namespace std;
typedef vector<int> vi;
typedef long long ll;
typedef pair<int,int> ii;
typedef vector<ii> vii;
typedef long double ld;
#define FOR(i,a,b) for(int i=a; i<b; i++)
#define ROF(i,a,b) for(int i=a; i>=b; i--)
#define pb push_back
#define fi first
#define se second
#define ms memset
int main(){
ios::sync_with_stdio(false);
cout.tie(0); cin.tie(0);
int n; cin>>n; vector<ll> a(n); FOR(i,0,n) cin>>a[i];
set<pair<ll,int>> A;
FOR(i,0,n) A.insert({-a[i],i});
vector<ll> pre(n+1); FOR(i,1,n+1) pre[i] = pre[i-1] + a[i-1];
stack<int> s; vi l(n), r(n), ans(n);
s.push(0); l[0]=-1;
FOR(i,1,n){
while (!s.empty()){
if (a[s.top()] <= a[i]){
s.pop();
}else break;
}
if (s.empty()) l[i]=-1;
else l[i] = s.top();
s.push(i);
}
while (!s.empty()) s.pop();
s.push(n-1); r[n-1] = n;
ROF(i,n-2,0){
while (!s.empty()){
if (a[s.top()] <= a[i]){
s.pop();
}else break;
}
if (s.empty()) r[i]=n;
else r[i] = s.top();
s.push(i);
}
while (!s.empty()) s.pop();
int q; cin>>q;
FOR(_,0,q){
int op; cin>>op;
if (op==1){
int pos, val; cin>>pos>>val; pos--;
A.erase({-a[pos],pos}); a[pos] = val; A.insert({-a[pos],pos});
FOR(i,pos+1,n+1){
pre[i] = pre[i-1] + a[i-1];
}
s.push(0); l[0]=-1;
FOR(i,1,n){
while (!s.empty()){
if (a[s.top()] <= a[i]){
s.pop();
}else break;
}
if (s.empty()) l[i]=-1;
else l[i] = s.top();
s.push(i);
}
while (!s.empty()) s.pop();
s.push(n-1); r[n-1] = n;
ROF(i,n-2,0){
while (!s.empty()){
if (a[s.top()] <= a[i]){
s.pop();
}else break;
}
if (s.empty()) r[i]=n;
else r[i] = s.top();
s.push(i);
}
while (!s.empty()) s.pop();
continue;
}
int L,R; cin>>L>>R; L--; R--;
FOR(i,L,R+1) ans[i]=0;
int answer = 0;
for (auto it = A.begin(); it != A.end(); it++){
int pos = (*it).se;
if (pos<L || R<pos) continue;
if (l[pos] < L && r[pos] > R){
ans[pos]=1; continue;
}
if (l[pos] >= L && pre[min(R+1,r[pos])]-pre[max(L,l[pos]+1)] >= a[l[pos]]) ans[pos] |= ans[l[pos]];
if (r[pos] <= R && pre[min(R+1,r[pos])]-pre[max(L,l[pos]+1)] >= a[r[pos]]) ans[pos] |= ans[r[pos]];
}
FOR(i,L,R+1) answer += ans[i];
FOR(i,L,R+1) ans[i] = 0;
cout<<answer<<"\n";
}
return 0;
}
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