Submission #1080902

#TimeUsernameProblemLanguageResultExecution timeMemory
1080902BuzzyBeezRoad Construction (JOI21_road_construction)C++17
18 / 100
10057 ms131072 KiB
#include <bits/stdc++.h> using namespace std; #define fi first #define se second const int N = 250000; vector<long long> tbc; void compress() {sort(tbc.begin(), tbc.end()); tbc.resize(unique(tbc.begin(), tbc.end()) - tbc.begin());} int order(long long key) {return lower_bound(tbc.begin(), tbc.end(), key) - tbc.begin() + 1;} struct Binary_Indexed_Tree { int bit[N * 3 + 8]; Binary_Indexed_Tree() {memset(bit, 0, sizeof bit);} void reset() {memset(bit, 0, sizeof bit);} int pt; void update(int u) { pt = u; while (pt <= N * 3) { ++bit[pt]; pt += (pt & -pt); } } int res; int pf(int u) { if (u <= 0) return 0; pt = u; res = 0; while (pt) { res += bit[pt]; pt -= (pt & -pt); } return res; } int range(int l, int r) {return pf(r) - pf(l - 1);} } tree; void rotate_45(pair<long long, long long>& pt) {pt.fi -= pt.se; pt.se += pt.fi + pt.se;} void rotate_45(pair<int, int>& pt) {pt.fi -= pt.se; pt.se += pt.fi + pt.se;} pair<long long, long long> raw[N + 8]; pair<int, int> A[N + 8]; pair<int, int> range_x[N + 8], range_y[N + 8]; vector<tuple<int, int, int>> Oy_Q[N * 3 + 8]; vector<int> Oy_U[N * 3 + 8]; int n, pt; void compress_all(long long radius) { tbc.resize(3 * n); pt = 0; for (int i = 1; i <= n; ++i) tbc[pt] = raw[i].fi, ++pt; for (int i = 1; i <= n; ++i) { tbc[pt] = raw[i].fi - radius - 1; ++pt; tbc[pt] = raw[i].fi + radius; ++pt; } compress(); for (int i = 1; i <= n; ++i) A[i].fi = order(raw[i].fi); for (int i = 1; i <= n; ++i) range_x[i] = make_pair(order(raw[i].fi - radius - 1), order(raw[i].fi + radius)); tbc.resize(3 * n); pt = 0; for (int i = 1; i <= n; ++i) tbc[pt] = raw[i].se, ++pt; for (int i = 1; i <= n; ++i) { tbc[pt] = raw[i].se - radius; ++pt; tbc[pt] = raw[i].se + radius; ++pt; } compress(); for (int i = 1; i <= n; ++i) A[i].se = order(raw[i].se); for (int i = 1; i <= n; ++i) range_y[i] = make_pair(order(raw[i].se - radius), order(raw[i].se + radius)); for (int i = 1; i <= n; ++i) { Oy_U[A[i].fi].push_back(A[i].se); Oy_Q[range_x[i].fi].push_back({range_y[i].fi, range_y[i].se, -1}); Oy_Q[range_x[i].se].push_back({range_y[i].fi, range_y[i].se, +1}); } } int ly, ry, coef, k; long long res; long long C(long long radius) { res = -n; compress_all(radius); for (int x = 1; x <= N * 3; ++x) { for (int y : Oy_U[x]) tree.update(y); for (auto item : Oy_Q[x]) { tie(ly, ry, coef) = item; res += tree.range(ly, ry) * coef; if (coef == 1 && res >= k * 2) { for (int i = 1; i <= N * 3; ++i) Oy_Q[i].clear(), Oy_U[i].clear(); tree.reset(); return k; } } } for (int i = 1; i <= N * 3; ++i) Oy_Q[i].clear(), Oy_U[i].clear(); tree.reset(); return res / 2; } map<long long, int> f; vector<int> Oy[N * 3 + 8]; long long dist(pair<long long, long long>& A1, pair<long long, long long>& A2) {return max(abs(A1.fi - A2.fi), abs(A1.se - A2.se));} long long dist(int i, int j) {return dist(raw[i], raw[j]);} multiset<pair<int, int>> active; int lx, rx; multiset<pair<int, int>>::iterator it; void find_all_connections(long long radius) { compress_all(radius); lx = 0; rx = 0; for (int i = 1; i <= n; ++i) Oy[A[i].fi].push_back(i); for (int i = 1; i <= n; ++i) { while (rx < range_x[i].se) { ++rx; for (int id : Oy[rx]) active.insert({A[id].se, id}); } while (lx < range_x[i].fi) { for (int id : Oy[lx]) active.erase(active.find({A[id].se, id})); ++lx; } it = active.lower_bound({range_y[i].fi, 0}); for (; it != active.end() && it->fi <= range_y[i].se; ++it) ++f[dist(i, it->se)]; } } signed main() { ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); cin >> n >> k; tbc.resize(3 * n); for (int i = 1; i <= n; ++i) cin >> raw[i].fi >> raw[i].se, rotate_45(raw[i]); sort(raw + 1, raw + n + 1); long long l = 1, r = 4e9, mid; while (l <= r) { mid = (l + r) / 2; if (C(mid) < k) l = mid + 1; else r = mid - 1; } // cout << l << '\n'; find_all_connections(l - 1); int cnt = 0; f.erase(0); for (auto item : f) { cnt += (item.second) / 2; for (int i = 0; i < item.second / 2; ++i) cout << item.first << '\n'; } while (cnt < k) cout << l << '\n', ++cnt; }
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