Submission #1079476

#	Time	Username	Problem	Language	Result	Execution time	Memory
1079476		ArthuroWich	Catfish Farm (IOI22_fish)	C++17	0 / 100	862 ms	2097152 KiB

fish

#include "fish.h"
#include<bits/stdc++.h>
using namespace std;
#define int long long int
int pref[3005][3005];
int query(int j, int i1, int i2) {
    if (i1 > i2) {
        return 0;
    }
    return pref[i2][j]-pref[i1-1][j];
}
int max_weights(int32_t N, int32_t M, vector<int32_t> X, vector<int32_t> Y, vector<int32_t> W) {
    int n = N, m = M, yn;
    yn = N;
    vector<vector<int>> c(yn+1, vector<int>(n+1, 0));
    vector<vector<vector<int>>> dp(yn+1, vector<vector<int>>(n+1, vector<int>(2, 0))); // 0 is increasing, 1 is decreasing, increasing can go to decreasing, decreasing cant go to increasing if next to eachother
    for (int i = 0; i < m; i++) {
        c[Y[i]+1][X[i]] = W[i];
        pref[Y[i]+1][X[i]] = W[i];
    }
    for (int j = 0; j < n; j++) {
        for (int i = 1; i <= yn; i++) {
            pref[i][j] += pref[i-1][j];
        }
    }
    for (int j = 1; j < n; j++) {
        int v = 0;
        dp[0][j][0] = max(dp[0][j][0], dp[0][j-1][0]);
        for (int i = 1; i <= yn; i++) {
            v += c[i][j];
            dp[0][j][0] = max(dp[0][j][0], dp[i][j-1][0]+v);
            dp[0][j][0] = max(dp[0][j][0], dp[i][j-1][1]+v);
        }
        for (int i = 1; i <= yn; i++) {
            for (int a = i; a <= yn; a++) {
                v = query(j, i+1, a);
                dp[i][j][1] = max(dp[i][j][1], dp[a][j-1][0]+v);
                dp[i][j][1] = max(dp[i][j][1], dp[a][j-1][1]+v);
            } 
            for (int a = 1; a <= i; a++) {
                v = query(j-1, a+1, i);
                dp[i][j][0] = max(dp[i][j][0], dp[a][j-1][0]+v);
            } 
        }
        if (j == 1) {
            v = 0;
            for (int i = 1; i <= yn; i++) {
                v += c[i][j-1];
                dp[i][j][0] = max(dp[i][j][0], dp[0][j-1][0]+v);
                dp[i][j][1] = max(dp[i][j][1], dp[0][j-1][0]+v);
            }
        }
        if (j-2 >= 0) {
            v = 0;
            for (int i = 1; i <= yn; i++) {
                v += c[i][j-1];
                dp[i][j][0] = max(dp[i][j][0], dp[0][j-2][0]+v);
                dp[i][j][1] = max(dp[i][j][1], dp[0][j-2][0]+v);
            }
        }
    }
    int ans = 0;
    for (int i = 0; i <= yn; i++) {
        ans = max(ans, dp[i][n-1][0]);
        ans = max(ans, dp[i][n-1][1]);
    }
    return ans;
}

• Subtask 1: 0 / 3
• Subtask 2: 0 / 6
• Subtask 3: 0 / 9
• Subtask 4: 0 / 14
• Subtask 5: 0 / 21
• Subtask 6: 0 / 17
• Subtask 7: 0 / 14
• Subtask 8: 0 / 16