Submission #1078667

#TimeUsernameProblemLanguageResultExecution timeMemory
1078667steveonalexSnowball (JOI21_ho_t2)C++17
100 / 100
78 ms18652 KiB
#include <bits/stdc++.h> using namespace std; typedef long long ll; typedef unsigned long long ull; #define MASK(i) (1LL << (i)) #define GETBIT(mask, i) (((mask) >> (i)) & 1) #define ALL(v) (v).begin(), (v).end() #define block_of_code if(true) ll max(ll a, ll b){return (a > b) ? a : b;} ll min(ll a, ll b){return (a < b) ? a : b;} ll gcd(ll a, ll b){return __gcd(a, b);} ll lcm(ll a, ll b){return a / gcd(a, b) * b;} ll LASTBIT(ll mask){return (mask) & (-mask);} int pop_cnt(ll mask){return __builtin_popcountll(mask);} int ctz(ull mask){return __builtin_ctzll(mask);} int logOf(ull mask){return 63 - __builtin_clzll(mask);} mt19937_64 rng(chrono::high_resolution_clock::now().time_since_epoch().count()); ll rngesus(ll l, ll r){return l + (ull) rng() % (r - l + 1);} double rngesus_d(double l, double r){ double cur = rngesus(0, MASK(60) - 1); cur /= MASK(60) - 1; return l + cur * (r - l); } template <class T1, class T2> bool maximize(T1 &a, T2 b){ if (a < b) {a = b; return true;} return false; } template <class T1, class T2> bool minimize(T1 &a, T2 b){ if (a > b) {a = b; return true;} return false; } template <class T> void printArr(T container, string separator = " ", string finish = "\n", ostream &out = cout){ for(auto item: container) out << item << separator; out << finish; } template <class T> void remove_dup(vector<T> &a){ sort(ALL(a)); a.resize(unique(ALL(a)) - a.begin()); } int main(void){ ios::sync_with_stdio(0);cin.tie(0); cout.tie(0); clock_t start = clock(); int n, q; cin >> n >> q; vector<ll> x(n); for(int i= 0; i<n; ++i) cin >> x[i]; vector<ll> queries(q+1); for(int i = 1; i<=q; ++i){ cin >> queries[i]; queries[i] += queries[i-1]; } vector<pair<ll, ll>> range(q+1, {0, 0}); vector<ll> sum(q+1); for(int i = 1; i<=q; ++i){ range[i] = range[i-1]; maximize(range[i].first, queries[i]); minimize(range[i].second, queries[i]); sum[i] = range[i].first - range[i].second; } vector<ll> ans(n); ans[0] -= range.back().second; ans.back() += range.back().first; for(int i = 1; i<n; ++i){ ll dis = x[i] - x[i-1]; if (dis >= sum.back()){ ans[i-1] += range.back().first; ans[i] -= range.back().second; } else{ int idx = lower_bound(ALL(sum), dis) - sum.begin(); pair<ll, ll> cur = range[idx-1]; if (queries[idx] >= 0) cur.first = dis + cur.second; else cur.second = cur.first - dis; ans[i-1] += cur.first; ans[i] -= cur.second; } } printArr(ans); cerr << "Time elapsed: " << clock() - start << " ms\n"; return 0; }
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