제출 #1078421

#제출 시각아이디문제언어결과실행 시간메모리
1078421oscar1fBroken Device (JOI17_broken_device)C++17
43 / 100
27 ms2732 KiB
#include<bits/stdc++.h>
#include "Annalib.h"
using namespace std;
using ll=long long;

static const ll TAILLE_MAX=150+5;
static bool estCache[TAILLE_MAX];
static ll nbVal;

static pair<bool,vector<ll>> calc(vector<ll> listeBit) {
    vector<ll> ans;
    ll pos=0;
    while (pos<nbVal) {
        if (!listeBit.empty() and !estCache[pos] and pos<nbVal-1 and (!estCache[pos+1] or listeBit.back()==0)) {
            ans.push_back(1);
            ans.push_back(listeBit.back());
            //cout<<1<<listeBit.back();
            listeBit.pop_back();
            pos+=2;
        }
        else {
            ans.push_back(0);
            //cout<<0;
            pos++;
        }
    }
    if (listeBit.empty()) {
        return {true,ans};
    }
    else {
        return {false,ans};
    }
} 

static void envoi(vector<ll> v) {
    for (int i=0;i<nbVal;i++) {
        Set(i,v[i]);
    }
}

void Anna(int N,ll X,int K,int P[]) {
    nbVal=N;
    ll obj=X;
    ll nbCache=K;
    for (ll i=0;i<nbVal;i++) {
        estCache[i]=false;
    }
    for (ll i=0;i<nbCache;i++) {
        estCache[P[i]]=true;
    }
    vector<ll> listeBit;
    while (obj>0) {
        listeBit.push_back(obj%2);
        obj/=2;
    }
    /*for (ll i:listeBit) {
        cout<<i;
    }
    cout<<endl;*/
    auto bonSens=calc(listeBit);
    if (bonSens.first) {
        envoi(bonSens.second);
    }
    else {
        for (ll i=0;i<(ll)listeBit.size();i++) {
            listeBit[i]=1-listeBit[i];
        } 
        envoi(calc(listeBit).second);
    }
    //cout<<endl;
}
#include<bits/stdc++.h>
#include "Brunolib.h"
using namespace std;
using ll=long long;

ll Bruno(int N,int A[]) {
    ll nbVal=N,pos=0,rep=0;
    vector<ll> recu;
    while (pos<nbVal) {
        if (A[pos]==1) {
            recu.push_back(A[pos+1]);
            pos+=2;
        }
        else {
            pos++;
        }
    }
    if (recu.empty()) {
        return rep;
    }
    if (recu[0]==0) {
        for (ll i:recu) {
            rep*=2;
            rep+=1-i;
        }
    }
    else {
        for (ll i:recu) {
            rep*=2;
            rep+=i;
        }
    }
    //cout<<"!"<<rep<<endl;
    return rep;
}
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