This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include<bits/stdc++.h>
#include<ext/pb_ds/assoc_container.hpp>
#include<ext/pb_ds/tree_policy.hpp>
#define pb push_back
#define int long long
#define vi vector<int>
#define vvi vector<vector<int>>
#define vll vector<long long int>
#define vvll vector<vector<long long int>>
#define pii pair<int, int>
#define vpii vector<pair<int, int>>
#define vc vector<char>
#define vvc vector<vector<char>>
#define vb vector<bool>
#define mii map<int,int>
#define mll map<long long int, long long int>
#define mivi map<int,vector<int>>
#define f0r(i,n) for(int i=0;i<n;i++)
#define FOR(i,k,n) for(int i=k;i<n;i++)
using namespace std;
using namespace __gnu_pbds;
typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> os;
signed main(){
ios::sync_with_stdio(false);
cin.tie(NULL);
//ifstream cin(".in");
//ofstream cout(".out");
int n,k,q;
cin>>n>>k>>q;
vi v(n);
f0r(i, n)cin>>v[i];
os s;
vpii w(n);
f0r(i, n){
w.pb({v[i], i});
}
sort(w.rbegin(), w.rend());
vi l(n, -1);
vi r(n, -1);
vi cur;
int mode = w[0].first;
f0r(i, n){
if(w[i].first == mode){
cur.pb(w[i].second);
}
else{
for(auto u : cur){
auto it = s.order_of_key(u);
if(it - 1 >= 0 && it - 1 < s.size())l[u] = *s.find_by_order(it-1);
else l[u] = -1;
//it++;
if(it >= 0 && it < s.size())r[u] = *s.find_by_order(it);
else r[u] = -1;
}
for(auto u : cur)s.insert(u);
mode = w[i].first;
cur = {w[i].second};
}
}
if(cur.size() > 0){
for(auto u : cur){
auto it = s.order_of_key(u);
if(it - 1 >= 0 && it - 1 < s.size())l[u] = *s.find_by_order(it-1);
else l[u] = -1;
//it++;
if(it >= 0 && it < s.size())r[u] = *s.find_by_order(it);
else r[u] = -1;
}
}
//f0r(i, n)cout<<r[i]<<' ';
//cout<<'\n';
while(q--){
int a,b;
cin>>a>>b;
a--;
b--;
//if(v[a] > v[b])swap(a, b);
queue<int>q;
q.push(a);
//do we need to calculate l[a] and r[a] for each a to make it faster?
//yes
//insert from low to high, do lowerbound to find left and right?
//pbds probably needed
vi dist(n, 4e18);
dist[a] = 0;
vb vis(n, 0);
vis[a] = 1;
while(!q.empty()){
int node = q.front();
q.pop();
vi nxt;
int mx = 0;
int p = node + 1;
while(p != -1 && p < n && mx < v[node]){
nxt.pb(p);
mx = v[p];
p = r[p];
}
mx = 0;
p = node - 1;
while(p >= 0 && mx < v[node]){
nxt.pb(p);
mx = v[p];
p = l[p];
}
for(auto u : nxt){
if(!vis[u]){
q.push(u);
vis[u] = 1;
dist[u] = min(dist[u], dist[node] + 1);
if(u == b)break;
}
}
}
//f0r(i, n)cout<<dist[i]<<' ';
//cout<<'\n';
cout<<dist[b]-1<<'\n';
}
}
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