Submission #1076773

#	Time	Username	Problem	Language	Result	Execution time	Memory
1076773		mickey080929	Soccer Stadium (IOI23_soccer)	C++17	1.50 / 100	386 ms	53816 KiB

soccer

#include "soccer.h"
#include <bits/stdc++.h>

using namespace std;

int dx[] = {1, -1, 0, 0};
int dy[] = {0, 0, 1, -1};

int biggest_stadium(int N, vector<vector<int>> F) {
    vector<vector<int>> vis(N, vector<int>(N, 0));
    queue<pair<int,int>> q;
    for (int i=0; i<N; i++) {
        for (int j=0; j<N; j++) {
            if (F[i][j] == 0) {
                vis[i][j] = 1;
                q.push({i, j});
                break;
            }
        }
        if (!q.empty()) break;
    }
    while (!q.empty()) {
        int x = q.front().first;
        int y = q.front().second;
        q.pop();
        for (int k=0; k<4; k++) {
            int nx = x + dx[k];
            int ny = y + dy[k];
            if (nx < 0 || nx >= N || ny < 0 || ny >= N) continue;
            if (vis[nx][ny]) continue;
            vis[nx][ny] = 1;
            q.push({nx, ny});
        }
    }
    for (int i=0; i<N; i++) {
        for (int j=0; j<N; j++) {
            if (F[i][j] == 0 && vis[i][j] == 0) {
                return 0;
            }
        }
    }
    int tot = 0;
    bool flag = false;
    int pl = -1, pr = -1;
    for (int i=0; i<N; i++) {
        int l = -1, r = -1, cnt = 0;
        for (int j=0; j<N; j++) {
            if (F[i][j] == 0) {
                if (l == -1) l = j;
                r = j;
                cnt ++;
            }
        }
        if (cnt == 0) {
            pl = -1; pr = -1;
            continue;
        }
        if (r - l + 1 != cnt) {
            return 0;
        }
        if (pl != -1) {
            if (!flag) {
                if (l <= pl && pr <= r) {}
                else if (pl <= l && r <= pr) {
                    flag = true;
                }
                else return 0;
            }
            else {
                if (pl <= l && r <= pr) {}
                else return 0;
            }
        }
        pl = l; pr = r;
        tot += cnt;
    }

    return tot;
}

• Subtask 0: 0 / 0
• Subtask 1: 1.5 / 6
• Subtask 2: 0 / 8
• Subtask 3: 0 / 22
• Subtask 4: 0 / 18
• Subtask 5: 0 / 16
• Subtask 6: 0 / 30