Submission #1076318

#	Time	Username	Problem	Language	Result	Execution time	Memory
1076318		c2zi6	Soccer Stadium (IOI23_soccer)	C++17	24 / 100	4512 ms	54608 KiB

soccer

#define _USE_MATH_DEFINES
#include <bits/stdc++.h>
#define ff first
#define ss second
#define pb push_back
#define all(a) (a).begin(), (a).end()
#define replr(i, a, b) for (int i = int(a); i <= int(b); ++i)
#define reprl(i, a, b) for (int i = int(a); i >= int(b); --i)
#define rep(i, n) for (int i = 0; i < int(n); ++i)
#define mkp(a, b) make_pair(a, b)
using namespace std;
typedef long long ll;
typedef long double ld;
typedef pair<int, int> PII;
typedef vector<int> VI;
typedef vector<PII> VPI;
typedef vector<VI> VVI;
typedef vector<VVI> VVVI;
typedef vector<VPI> VVPI;
typedef pair<ll, ll> PLL;
typedef vector<ll> VL;
typedef vector<PLL> VPL;
typedef vector<VL> VVL;
typedef vector<VVL> VVVL;
typedef vector<VPL> VVPL;
template<class T> T setmax(T& a, T b) {if (a < b) return a = b; return a;}
template<class T> T setmin(T& a, T b) {if (a < b) return a; return a = b;}
#include <ext/pb_ds/assoc_container.hpp>
using namespace __gnu_pbds;
template<class T>
using indset = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
#include "soccer.h"

int n;
VVI a;
VVI prefv;
VVI prefh;

bool canv(int ux, int uy, int vx, int vy) {
    int y = uy;
    int l, r;
    if (ux < vx) l = ux, r = vx;
    else l = vx, r = ux;
    return (prefv[r+1][y] - prefv[l][y]) == 0;
}

bool canh(int ux, int uy, int vx, int vy) {
    int x = ux;
    int l, r;
    if (uy < vy) l = uy, r = vy;
    else l = vy, r = uy;
    return (prefh[x][r+1] - prefh[x][l]) == 0;
}

bool can1(int ux, int uy, int vx, int vy) {
    return canv(ux, uy, vx, uy) && canh(vx, uy, vx, vy);
}
bool can2(int ux, int uy, int vx, int vy) {
    return canh(ux, uy, ux, vy) && canv(ux, vy, vx, vy);
}

bool can(int ux, int uy, int vx, int vy) {
    return can1(ux, uy, vx, vy) || can2(ux, uy, vx, vy);
}

bool can() {
    rep(ux, n) rep(uy, n) if (a[ux][uy] == 0) {
        rep(vx, n) rep(vy, n) if (a[vx][vy] == 0) {
            if (can(ux, uy, vx, vy));
            else return 0;
        }
    }
    return true;
}

int biggest_stadium(int N, VVI A_ARG) {
    n = N;
    a = A_ARG;
    rep(_, 1) {
        int x, y;
        int cnt = 0;
        rep(i, n) rep(j, n) if (a[i][j] == 1) x = i, y = j, cnt++;
        if (cnt == 0) return n*n;
        if (cnt > 1) break;
        int ans = 0;
        setmax(ans, n*n - (x+1)*(y+1));
        setmax(ans, n*n - (x+1)*(n-y));
        setmax(ans, n*n - (n-x)*(y+1));
        setmax(ans, n*n - (n-x)*(n-y));
        return ans;
    }
    prefv = prefh = VVI(n+1, VI(n+1));
    rep(i, n) {
        rep(j, n) prefh[i][j+1] = prefh[i][j] + a[i][j];
    }
    rep(j, n) {
        rep(i, n) prefv[i+1][j] = prefv[i][j] + a[i][j];
    }


    if (N <= 3) {
        int ans = 0;
        VVI atmp = a;
        rep(s, (1<<(n*n))) {
            a = atmp;
            rep(i, n) rep(j, n) if (a[i][j] == 0) {
                a[i][j] = (s & (1<<(n*i+j)));
            }
            if (can()) {
                int cur = 0;
                rep(i, n) rep(j, n) if (a[i][j] == 0) cur++;
                setmax(ans, cur);
            }
        }
        return ans;
    }

    if (!can()) return 0;
    int ans = 0;
    rep(i, n) rep(j, n) if (a[i][j] == 0) ans++;
    return ans;
}

• Subtask 0: 0 / 0
• Subtask 1: 6 / 6
• Subtask 2: 8 / 8
• Subtask 3: 5.5 / 22
• Subtask 4: 4.5 / 18
• Subtask 5: 0 / 16
• Subtask 6: 0 / 30