#include <bits/stdc++.h>
using namespace std;
using ll=long long;
// #define int long long
const int M=310;
const ll inf=3e18;
int m;
ll L, a[M*2];
void impossible(){
cout << "impossible\n";
exit(0);
}
pair<pair<ll, ll>, vector<ll>> dp(ll power2, pair<pair<ll, ll>, vector<ll>> start, vector<pair<ll, ll>> v){
ll tl=start.first.first, tr=start.first.second;
vector<ll> f=start.second;
ll szl=max(0ll, min(m*m*2ll, (tl-(-inf))/power2));
ll szr=max(0ll, min(m*m*2ll, (inf-tr)/power2));
tl-=szl*power2, tr+=szr*power2;
reverse(f.begin(), f.end());
f.resize((int)f.size()+szl, -1);
reverse(f.begin(), f.end());
f.resize((int)f.size()+szr, -1);
for (auto &i:v){
ll val=i.first, cnt=i.second;
if (val>0){
for (int j=(int)f.size()-1; j>=val; --j){
if (f[j-val]!=-1) f[j]=max(f[j], f[j-val]+cnt);
}
}else{
for (int j=0; j-val<(int)f.size(); ++j){
if (f[j-val]!=-1) f[j]=max(f[j], f[j-val]+cnt);
}
}
}
reverse(f.begin(), f.end());
while (f.size() && f.back()==-1){
tl+=power2;
f.pop_back();
}
reverse(f.begin(), f.end());
while (f.size() && f.back()==-1){
tr-=power2;
f.pop_back();
}
if (f.empty()) impossible();
return {{tl, tr}, f};
}
vector<pair<ll, ll>> v[50];
int32_t main(){
ios_base::sync_with_stdio(false);
cin.tie(nullptr);
cin >> m >> L;
for (int i=-m; i<=m; ++i) cin >> a[m+i];
for (int i=-m; i<=m; ++i) if (i){
ll val=i, cnt=0;
while (val%2==0) val/=2, ++cnt;
for (int j=0; j<50; ++j) if (a[m+i]>=(1ll<<j)) v[j+cnt].emplace_back(val, 1ll<<j), a[m+i]-=1ll<<j;
for (int j=0; j<50; ++j) if (a[m+i]>>j&1) v[j+cnt].emplace_back(val, 1ll<<j);
}
pair<pair<ll, ll>, vector<ll>> f={{0, 0}, {a[m]}};
for (int i=0; i<50; ++i){
f=dp(1ll<<i, f, v[i]);
if (abs(f.first.first-L)>>i&1){
f.first.first+=1ll<<i;
if (f.second.empty()) impossible();
f.second.erase(f.second.begin());
}
if (abs(f.first.second-L)>>i&1){
f.first.second-=1ll<<i;
if (f.second.empty()) impossible();
f.second.pop_back();
}
vector<ll> tmp;
for (int j=0; j<(int)f.second.size(); j+=2) tmp.push_back(f.second[j]);
tmp.swap(f.second);
}
if (f.first.first>L || f.first.second<L) impossible();
cout << f.second[(L-f.first.first)>>50] << '\n';
return 0;
}
