This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
// header file
#include <bits/stdc++.h>
// pragma
#pragma GCC optimize("Ofast")
#pragma GCC optimize("unroll-loops")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
// macros
#define endl "\n"
#define ll long long
#define mp make_pair
#define ins insert
#define lb lower_bound
#define pb push_back
#define ub upper_bound
#define lll __int128
#define fi first
#define se second
using namespace std;
const int lim = 6e5 + 5;
struct fenwick {
int a[lim];
fenwick() {
memset(a, 0, sizeof(a));
}
void update(int idx, int val) {
// cerr << idx << endl;
assert(idx > 0);
while(idx < lim) {
a[idx] += val;
idx += idx&-idx;
}
}
void update(int l, int r, int val) {
if(l > r)
return;
update(l, val);
update(r + 1, -val);
}
int query(int idx) {
if(idx >= lim)
idx = lim - 1;
int res = 0;
while(idx) {
res += a[idx];
idx -= idx&-idx;
}
return res;
}
} cur;
struct disjoint_setr {
int par[lim], sz[lim], h[lim];
void reset() {
for (int i = 0; i < lim; i++) {
par[i] = h[i] = i;
sz[i] = 1;
}
}
disjoint_setr() {
reset();
}
int rep(int x) {
return par[x] == x ? x : par[x] = rep(par[x]);
}
int nxt(int x) { return h[rep(x)]; }
void erase(int x) { merge(x, x + 1); }
void merge(int x, int y) {
x = rep(x), y = rep(y);
if(x != y) {
if (sz[x] < sz[y]) swap(x, y);
par[y] = x;
h[x] = max(h[x], h[y]);
sz[x] += sz[y];
}
}
} redr, bluer;
struct disjoint_setl {
int par[lim], sz[lim], h[lim];
void reset() {
for (int i = 0; i < lim; i++) {
par[i] = h[i] = i;
sz[i] = 1;
}
}
disjoint_setl() {
reset();
}
int rep(int x) {
return par[x] == x ? x : par[x] = rep(par[x]);
}
int prv(int x) { return h[rep(x)]; }
void erase(int x) { merge(x - 1, x); }
void merge(int x, int y) {
x = rep(x), y = rep(y);
if(x != y) {
if (sz[x] < sz[y]) swap(x, y);
par[y] = x;
h[x] = min(h[x], h[y]);
sz[x] += sz[y];
}
}
} redl, bluel;
int main() {
ios_base::sync_with_stdio(0); cin.tie(NULL);
int n;
cin >> n;
int a[2 * n + 5];
for(int i = 1; i <= 2 * n; ++i)
cin >> a[i];
int b[n + 5], c[n + 5];
for(int i = 1; i <= n; ++i)
cin >> b[i];
for(int i = 1; i <= n; ++i)
cin >> c[i];
sort(b + 1, b + n + 1);
sort(c + 1, c + n + 1);
int l = 0, r = 1e9, res = -1;
vector<pair<int, int>> v;
for(int i = 1; i <= 2 * n; ++i)
v.pb(mp(a[i], i));
sort(v.begin(), v.end());
pair<int, int> validb[2 * n + 5], validr[2 * n + 5];
while(l <= r) {
memset(cur.a, 0, sizeof(cur.a));
redl.reset();
redr.reset();
bluel.reset();
bluer.reset();
int mid = (l + r) >> 1;
// max diff -> mid
// try each partition what is the max diff
// nanti ada banyak validity test, tinggal cek validity testnya mana aja
for(int i = 1; i <= 2 * n; ++i) {
// idx of element >= a[i] - mid
validb[i].fi = lower_bound(b + 1, b + n + 1, a[i] - mid) - b;
// idx of element <= a[i] + mid
validb[i].se = upper_bound(b + 1, b + n + 1, a[i] + mid) - b - 1;
// idx of element >= a[i] - mid
validr[i].fi = lower_bound(c + 1, c + n + 1, a[i] - mid) - c;
// idx of element <= a[i] + mid
validr[i].se = upper_bound(c + 1, c + n + 1, a[i] + mid) - c - 1;
// if(mid == 1) {
// cerr << a[i] + mid << " " << upper_bound(c + 1, c + n + 1, a[i] + mid) - c - 1 << " " << validr[i].se << endl;
// }
}
// cerr << "TEST" << endl;
for(auto p : v) {
// process
// cerr << "UPDATE" << endl;
cur.update(max(1, p.se - n + 1), p.se, 1);
// observe that blue on left/right of that segment can be invalid
int idx = p.se;
// cerr << "TEST" << endl;
int val;
while((val = bluer.nxt(max(1, p.se - n + 1))) <= p.se && val > 0) {
int tmp2 = cur.query(val);
if(tmp2 < validb[idx].fi || tmp2 > validb[idx].se)
bluer.erase(val), bluel.erase(val);
else
break;
}
while((val = bluel.prv(p.se)) >= max(1, p.se - n + 1)) {
int tmp2 = cur.query(val);
if(tmp2 < validb[idx].fi || tmp2 > validb[idx].se)
bluer.erase(val), bluel.erase(val);
else
break;
}
// cerr << "DONE" << endl;
if(p.se <= n) {
cur.update(p.se + n + 1, 2 * n, 1);
// observe that blue on left/right of that segment can be invalid
while((val = bluer.nxt(p.se + n + 1)) <= 2 * n) {
// cerr << val << endl;
int tmp2 = cur.query(val);
// cerr << "AFTER" << endl;
if(tmp2 < validb[idx].fi || tmp2 > validb[idx].se) {
bluer.erase(val), bluel.erase(val);
// cerr << "HERE" << endl;
}
else
break;
}
// cerr << "CHECK" << endl;
while((val = bluel.prv(2 * n)) >= p.se + n + 1) {
// cerr << val << endl;
int tmp2 = cur.query(val);
if(tmp2 < validb[idx].fi || tmp2 > validb[idx].se)
bluer.erase(val), bluel.erase(val);
else
break;
}
}
// cerr << "TEST2" << endl;
while((val = redr.nxt(max(1, p.se - n + 1))) <= p.se && val > 0) {
// cerr << "check " << *it << " due to " << p.se << " " << cur.query(*it) << " " << validr[idx].fi << endl;
int tmp2 = cur.query(val);
if(tmp2 < validr[idx].fi || tmp2 > validr[idx].se)
redr.erase(val), redl.erase(val);
else
break;
}
while((val = redl.prv(p.se)) >= max(1, p.se - n + 1)) {
// cerr << "check " << *it << " due to " << p.se << " " << cur.query(*it) << " " << validr[idx].se << endl;
int tmp2 = cur.query(val);
if(tmp2 < validr[idx].fi || tmp2 > validr[idx].se)
redr.erase(val), redl.erase(val);
else
break;
}
if(p.se <= n) {
// observe that red on left/right of that segment can be invalid
while((val = redr.nxt(p.se + n + 1)) <= 2 * n) {
// cerr << "check " << *it << " due to " << p.se << " " << cur.query(*it) << " " << validr[idx].fi << endl;
int tmp2 = cur.query(val);
if(tmp2 < validr[idx].fi || tmp2 > validr[idx].se)
redr.erase(val), redl.erase(val);
else
break;
}
while((val = redl.prv(2 * n)) >= p.se + n + 1) {
// cerr << "check " << *it << " due to " << p.se << " " << cur.query(*it) << " " << validr[idx].se << endl;
int tmp2 = cur.query(val);
if(tmp2 < validr[idx].fi || tmp2 > validr[idx].se)
redr.erase(val), redl.erase(val);
else
break;
}
}
// cerr << "FINISH" << endl;
}
// blue and red have to complement each other
bool ans = 0;
// cerr << "MID IS " << mid << endl;
for(int i = 1; i + n <= 2 * n; ++i) {
// cerr << i << " " << i + n << endl;
// cerr << bluel.prv(i) << " " << bluel.prv(i + n) << endl;
// cerr << redl.prv(i) << " " << redl.prv(i + n) << endl;
if((bluel.prv(i) == i && redl.prv(i + n) == i + n) || (redl.prv(i) == i && bluel.prv(i + n) == i + n))
ans = 1;
// cerr << "DONE" << endl;
}
/*
if(mid <= 20) {
cerr << "DEBUG " << mid << endl;
for(auto x : red) {
cerr << x << " ";
}
cerr << endl;
for(auto x : blue) {
cerr << x << " ";
}
cerr << endl;
}
*/
if(ans)
r = mid - 1, res = mid;
else
l = mid + 1;
}
cout << res << endl;
// choose a contiguous segment L to R such that we use one color
// N^2 approach -> pair greedily (sorted)
// int res = 1e9;
// for(int i = 1; i + n <= 2 * n + 1; ++i) {
// vector<int> blue, red;
// for(int j = 1; j < i; ++j) {
// blue.pb(a[j]);
// }
// for(int j = i; j < i + n; ++j) {
// red.pb(a[j]);
// }
// for(int j = i + n; j <= 2 * n; ++j) {
// blue.pb(a[j]);
// }
// sort(blue.begin(), blue.end());
// sort(red.begin(), red.end());
// int mx = 0;
// for(int k = 1; k <= n; ++k) {
// mx = max({mx, abs(blue[k - 1] - b[k]), abs(red[k - 1] - c[k])});
// }
// res = min(res, mx);
// mx = 0;
// swap(red, blue);
// for(int k = 1; k <= n; ++k) {
// mx = max({mx, abs(blue[k - 1] - b[k]), abs(red[k - 1] - c[k])});
// }
// res = min(res, mx);
// }
// cout << res << endl;
return 0;
}
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