Submission #1074095

#	Time	Username	Problem	Language	Result	Execution time	Memory
1074095		Gromp15	Catfish Farm (IOI22_fish)	C++17	12 / 100	201 ms	40876 KiB

fish

#include <bits/stdc++.h>
#pragma GCC optimize("O3")
#pragma GCC target("avx2")
#include "fish.h"
#define ll long long
#define ar array
#define sz(x) (int)x.size()
#define all(x) x.begin(), x.end()
using namespace std;

const ll INF = 1e18;
template<typename T> bool ckmin(T &a, const T &b ) { return a > b ? a = b, 1 : 0; }
template<typename T> bool ckmax(T &a, const T &b ) { return a < b ? a = b, 1 : 0; }

long long max_weights(int n, int m, std::vector<int> x, std::vector<int> y, std::vector<int> w) {
	vector<vector<ar<ll, 2>>> each(n);
	for (int i = 0; i < m; i++) {
		each[x[i]].push_back({y[i], w[i]});
	}
	for (int i = 0; i < n; i++) {
		sort(all(each[i]));
		vector<ar<ll, 2>> nw;
		bool F = 0;
		ll s = 0;
		for (int j = 0; j < sz(each[i]); j++) {
			if (!each[i][j][0]) F = 1;
			nw.push_back({each[i][j][0] - 1, s});
			s += each[i][j][1];
		}
		if (!F) nw.push_back({-1, 0});
		nw.push_back({n - 1, s});
		sort(all(nw));
		swap(each[i], nw);
	}
	vector<vector<ll>> dp;
	auto query = [&](int pos, int x) {
		return prev(upper_bound(all(each[pos]), ar<ll, 2>{x, LLONG_MAX})) - each[pos].begin();
	};
	vector<vector<ar<int, 3>>> val(n);
	for (int i = 0; i < n; i++) {
		val[i].resize(sz(each[i]));
		for (int k = 0; k < sz(each[i]); k++) {
			for (int j = -1; j <= 1; j++) {
				if (i + j >= 0 && i + j < n) {
					val[i][k][j+1] = query(i + j, each[i][k][0]);
				}
			}
		}
	}
	for (int i = 0; i < n; i++) {
		vector<vector<ll>> dp2;
		const int N = sz(each[i]);
		dp2.resize(i ? sz(each[i-1]) : 1, vector<ll>(N, -INF));
		if (!i) {
			for (int j = 0; j < N; j++) {
				dp2[0][j] = 0;
			}
			swap(dp, dp2);
		}
		else {
			for (int j = 0; j < sz(dp); j++) {
				for (int k = 0; k < sz(dp[j]); k++) {
					for (int l = 0; l < N; l++) {
						int L = k, R = max(i-2 >= 0 ? val[i-2][j][2] : 0, val[i][l][0]);
						ckmax(dp2[k][l], dp[j][k] + (L <= R ? each[i-1][R][1] - each[i-1][L][1] : 0));
					}
				}
			}
			swap(dp, dp2);
		}
	}
	ll ans = -INF;
	for (int i = 0; i < sz(dp); i++) {
		for (int j = 0; j < sz(dp[i]); j++) {
			int L = j, R = val[n-2][i][2];
			ckmax(ans, dp[i][j] + (L <= R ? each[n-1][R][1] - each[n-1][L][1] : 0));
		}
	}
	return ans;
}

• Subtask 1: 3 / 3
• Subtask 2: 0 / 6
• Subtask 3: 9 / 9
• Subtask 4: 0 / 14
• Subtask 5: 0 / 21
• Subtask 6: 0 / 17
• Subtask 7: 0 / 14
• Subtask 8: 0 / 16