# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
1073582 | coolboy19521 | Energetic turtle (IZhO11_turtle) | C++17 | 2093 ms | 1504 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
// Thanks Benq
#include "bits/stdc++.h"
#define ll long long
#define int ll
using namespace std;
const int sz = 6e5 + 1;
const int sm = 25;
vector<pair<int,int>> vp;
vector<int> ps;
ll wz[sm][sm];
ll dp[sm][sm];
bool sv[sz];
ll bpw(ll x, ll b, ll z) {
ll r = 1;
while (b) {
if (b & 1)
(r *= x) %= z;
(x *= x) %= z;
b >>= 1;
}
return r;
}
ll nck(ll n, ll k, ll z) {
if (n < k || n < 0) return 0;
if (k == 0 || n == k) return 1;
if (k == 1 || k == n - 1) return n;
ll r = 1;
k = min(k, n - k);
for (ll p : ps) {
if (p > n) break;
int e = 0;
for (ll c = p; c <= n; c *= p) {
if (c <= k) e -= k / c;
if (c <= n - k) e -= (n - k) / c;
e += n / c;
}
(r *= bpw(p, e, z)) %= z;
}
return r;
}
ll gt(pair<int,int>& f, pair<int,int>& s, int z) {
int xds = s.first - f.first;
int yds = s.second - f.second;
return nck(xds + yds, yds, z);
}
ll sb(ll a, ll b, ll z) {
return (a + z - b) % z;
}
ll ml(ll a, ll b, ll z) {
return a * b % z;
}
ll ad(ll a, ll b, ll z) {
return (a + b) % z;
}
signed main() {
cin.tie(nullptr)->sync_with_stdio(false);
ll n, m, k, t, z;
cin >> n >> m >> k >> t >> z;
int sd = n + m + 2;
for (ll i = 2; i < sd; i ++) {
if (sv[i]) continue;
ps.push_back(i);
sv[i] = true;
for (ll j = i * i; j < sd; j += i)
sv[j] = true;
}
for (int i = 0; i < k; i ++) {
int x, y;
cin >> x >> y;
vp.push_back(make_pair(x, y));
}
vp.push_back(make_pair(0, 0));
vp.push_back(make_pair(n, m));
sort(begin(vp), end(vp));
k = vp.size();
for (int i = 1; i < k; i ++) {
vector<int> an(k + 2);
for (int j = i - 1; 0 <= j; j --) {
wz[j][i] = an[j] = gt(vp[j], vp[i], z);
for (int l = j + 1; l < i; l ++)
wz[j][i] = sb(wz[j][i], ml(wz[j][l], an[l], z), z);
}
}
dp[0][1] = 1;
for (int i = 1; i < k; i ++)
for (int j = 0; j < i; j ++)
for (int l = 2; l <= min(i + 1, t + 2); l ++)
dp[i][l] = ad(dp[i][l], ml(dp[j][l - 1], wz[j][i], z), z);
ll r = 0;
for (int i = 1; i <= t + 2; i ++)
r = ad(r, dp[k - 1][i], z);
cout << r << '\n';
}
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---|---|---|---|---|
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