Submission #1071013

#TimeUsernameProblemLanguageResultExecution timeMemory
1071013pawnedCircle selection (APIO18_circle_selection)C++17
0 / 100
3097 ms70848 KiB
#pragma GCC optimize("O1,O2,O3,Ofast,unroll-loops") #include <bits/stdc++.h> using namespace std; #define fi first #define se second #define pb push_back typedef long long ll; typedef pair<int, int> ii; typedef vector<int> vi; const char nl = '\n'; void fastIO() { ios::sync_with_stdio(false); cin.tie(0); } bool intersect(int &x1, int &y1, int &x2, int &y2, int &r1, int &r2) { ll dx = abs(x1 - x2); ll dy = abs(y1 - y2); ll dt = r1 + r2; if (dt * dt >= dx * dx + dy * dy) return true; return false; } int main() { fastIO(); int N; cin>>N; vector<pair<ii, int>> cr(N); // {{x, y}, r} set<pair<ii, ii>> all; // {{r, -id}, {x, y}} map<int, set<pair<int, ii>>> allx; // maps x coord to all {y, {r, id}} for (int i = 0; i < N; i++) { int x, y, r; cin>>x>>y>>r; all.insert({{r, -i}, {x, y}}); allx[x].insert({y, {r, i}}); } vi par(N, -1); int rem = N; while (rem > 0) { auto it = --all.end(); int r = (*it).fi.fi; int id = -(*it).fi.se; int x = (*it).se.fi; int y = (*it).se.se; // cout<<"at "<<id<<endl; // consider all from x in x-2r to x+2r, y in y-2r to r+2r int xl = max((ll)(x) - 2 * (ll)(r), (ll)(-2e9)); int xh = min((ll)(x) + 2 * (ll)(r), (ll)(2e9)); auto it2 = allx.lower_bound(xl); bool done = true; while (it2 != allx.end() && (*it2).fi <= xh) { // do another search inside int cx = (*it2).fi; vector<pair<ll, ii>> toremove; int dx = abs(x - cx); // can do up to sqrt for yh ll dy = (ll)(pow(4 * (double)(r) * (double)(r) - (double)(dx) * (double)(dx), 0.5) + 1); int yl = max((ll)(y) - dy, (ll)(-2e9)); int yh = min((ll)(y) + dy, (ll)(2e9)); auto it3 = allx[cx].lower_bound({yl, {-1, -1}}); while (it3 != allx[cx].end() && (*it3).fi <= yh) { int cy = (*it3).fi; int cr = (*it3).se.fi; if (intersect(x, y, cx, cy, r, cr)) { toremove.pb(*it3); done = true; break; } it3++; } for (pair<int, ii> p : toremove) { par[p.se.se] = id; // cout<<"erased "<<p.se.se<<endl; allx[cx].erase(p); all.erase({{p.se.fi, -p.se.se}, {cx, p.fi}}); rem--; } if (done) break; it2++; } } // cout<<"ANSWER: "; for (int x : par) cout<<(x + 1)<<" "; cout<<endl; }
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