Submission #1070809

#TimeUsernameProblemLanguageResultExecution timeMemory
1070809MohamedFaresNebiliClosing Time (IOI23_closing)C++17
0 / 100
1034 ms43324 KiB
#include <bits/stdc++.h> #include "closing.h" using namespace std; vector<pair<int, long long>> adj[200005]; long long D[200005][2]; vector<long long> pL, pR, pM; void dfs(int X, int p, int st) { for(auto u : adj[X]) { if(u.first == p) continue; D[u.first][st] = D[X][st] + u.second; dfs(u.first, X, st); } } long long sum(int l, int r, vector<long long> arr) { return arr[r] - (l > 0 ? arr[l - 1] : 0); } int max_score(int N, int X, int Y, long long K, vector<int> U, vector<int> V, vector<int> W) { pL.resize(N); pR.resize(N); pM.resize(N); for(int l = 0; l < N; l++) D[l][0] = D[l][1] = 2e18 + 7, adj[l].clear(); for(int l = 0; l < N - 1; l++) { adj[U[l]].push_back({V[l], W[l]}); adj[V[l]].push_back({U[l], W[l]}); } if(X > Y) swap(X, Y); D[X][0] = 0, D[Y][1] = 0; dfs(X, X, 0); dfs(Y, Y, 1); for(int l = 0; l < N; l++) { pL[l] = D[l][0]; pR[l] = D[l][1]; pM[l] = min(D[l][0], D[l][1]); if(l > 0) { pL[l] += pL[l - 1]; pR[l] += pR[l - 1]; pM[l] += pM[l - 1]; } } priority_queue<pair<int, int>, vector<pair<int, int>>, greater<pair<int, int>>> Q; Q.push({0, X}); Q.push({0, Y}); vector<long long> dist(N, 1e18); dist[X] = dist[Y] = 0; int res = 0; long long cur = 0; while(!Q.empty()) { int A = Q.top().second; long long B = Q.top().first; Q.pop(); if(cur + B > K) break; cur += B; res++; for(auto u : adj[A]) { if(dist[u.first] > dist[A] + u.second) { dist[u.first] = dist[A] + u.second; Q.push({dist[u.first], u.first}); } } } for(int l = 0; l <= N; l++) { for(int i = l; i <= N; i++) { long long calc = sum(l, i, pL) + sum(l, i, pR) - sum(l, i, pM); if(calc > K) continue; int cur = i - l + 1; priority_queue<pair<int, long long>, vector<pair<int, long long>>, greater<pair<int, long long>>> pq; if(i < N - 1) pq.push({D[i + 1][1], i + 1}); if(l > 0) pq.push({D[l - 1][0], l - 1}); while(!pq.empty()) { int x = pq.top().second; long long w = pq.top().first; pq.pop(); calc += w; if(calc > K) break; ++cur; if(x > i && x < N - 1) pq.push({D[x + 1][1], x + 1}); if(x < l && x > 0) pq.push({D[x - 1][0], x - 1}); } res = max(res, cur); } } return res; }
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