This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include "longesttrip.h"
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef vector<int> vi;
typedef vector<vi> vii;
typedef pair<int,int> pi;
typedef vector<pi> pii;
typedef tuple<int,int,int> tii;
typedef vector<ll> li;
typedef vector<li> lii;
#define REP(i,a,b) for(int i=a;i<b;i++)
#define F first
#define S second
#define PB push_back
#define MP make_pair
#define LSOne(s) ((s)&(-s))
ll INF=1e18+10;
int inf=1e9+10;
ll M=1e9+7;
int solve(int bk,int p,int n){
vi a,b,x;
x.PB(bk);
REP(i,p,n){
a.clear();
a.PB(x.back());
b.clear();
b.PB(i);
if(are_connected(a,b))x.PB(i);
else return i;
}
return n;
}
std::vector<int> longest_trip(int n, int d)
{
if(d==3){
vi ans;
REP(i,0,n)ans.PB(i);
return ans;
}
if(d==2){
deque<int> dq;
vi a,b;
a.PB(0);b.PB(1);
if(are_connected(a,b)){
dq.PB(0);
dq.PB(1);
b.pop_back();b.PB(2);
if(are_connected(a,b))dq.push_front(2);
else dq.push_back(2);
}
else{
dq.PB(0);
dq.PB(2);
dq.PB(1);
}
REP(i,3,n){
a.clear();b.clear();
a.PB(dq.back());b.PB(i);
if(are_connected(a,b))dq.push_back(i);
else dq.push_front(i);
}
vi ans;
REP(i,0,n){
ans.PB(dq.front());
dq.pop_front();
}
return ans;
}
vi ans;
vi a,b,x,y;
x.PB(0);
int tm=solve(0,1,n);
REP(i,0,tm)x.PB(i);
if(tm!=n)y.PB(tm);
if(y.empty())return x;
int pos=tm+1;
while(pos<n){
a.clear();b.clear();
a.PB(x.back());b.PB(pos);
bool f1=are_connected(a,b);
a.clear();b.clear();
a.PB(y.back());b.PB(pos);
bool f2=are_connected(a,b);
if(f1&&f2){
x.PB(pos);
reverse(y.begin(),y.end());
for(auto u:y)x.PB(u);
y.clear();
int tmp=solve(x.back(),pos+1,n);
REP(i,pos,tmp)x.PB(i);
if(tmp==n)return x;
y.PB(tmp);
pos=tmp+1;
}
else if(f1){
x.PB(pos);
pos++;
}
else if(f2){
y.PB(pos);
pos++;
}
else{
reverse(y.begin(),y.end());
for(auto u:y)x.PB(u);
y.clear();
int tmp=solve(x.back(),pos,n);
REP(i,pos,tmp)x.PB(i);
if(tmp==n)return x;
y.PB(tmp);
pos=tmp+1;
}
}
if(x.size()>=y.size())return x;
else return y;
return ans;
}
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