Submission #1068126

#	Time	Username	Problem	Language	Result	Execution time	Memory
1068126		lollipop	COVID tests (CEOI24_covid)	C++17	26.95 / 100	2137 ms	464 KiB

Main

#include<bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/rope>
#define int long long
#define pb push_back
#define s second
#define f first
#define pf push_front
#define inf 100000000000000000
#define bitebi __builtin_popcountll
#define FOR( i , n ) for( int i = 0 ; i < n ; i ++ )
#define YES cout <<"YES\n"
#define NO cout << "NO\n"
#define debug cout << "Here Fine" << endl ;
#define pr pair < int , int >
#define fbo find_by_order // returns iterator
#define ook order_of_key // returns strictly less numbers than key
using namespace std ;
//#pragma GCC optimize("Ofast")
//#pragma GCC target("avx,avx2,fma")
using namespace __gnu_pbds;
using namespace __gnu_cxx;
template<class T> using ordered_set =tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update> ;
const double Pi=acos(-1.0);
const double EPS=1E-8;
const int mod =  1000000007 ;
const int mod1 = 998244353 ;
const int N = 3e5 + 10 ;
mt19937 R(time(0));
map < int , int > ma , ma1 ;

int n , t , T ;
double p ;
string s = "" , ans = "" ;


void go( int l , int r ){
	for( int i = l ; i <= r ; i ++ ) s[ i ] = '1' ;
	cout << "Q " << s << endl ;
	char c ; cin >> c ;
	for( int i = l ; i <= r ; i ++ ) s[ i ] = '0' ;
	
	if( c == 'N' ) return ;
	
	if( l == r ){
		ans[ l ] = '1' ; return ; 
	}
	int mid = ( l + r ) / 2 ; 
	go( l , mid ) ;
	go( mid + 1 , r ) ;
	
}

void solve(){

	FOR( i , n ) s[ i ] = ans[ i ] = '0' ;
	
	
	if( T == 1 ){
		FOR( i , n ){
			s[ i ] = '1' ;
			cout << "Q " << s << endl ;
			s[ i ] = '0' ;
			char c ; cin >> c ;
			if( c == 'P' ) ans[ i ] = '1' ;
		}
		cout << "A " << ans << endl ;
		char c ; cin >> c ;
		if( c == 'W' ) return ; 
	}
	
	
	// else go binary search?
	
	
	
	go( 0 , n - 1 ) ; 
	cout << "A " << ans << endl ;
	char c ; cin >> c ;
	
	
	
}
signed main() {
   ios_base::sync_with_stdio(0),cin.tie(NULL),cout.tie(NULL);
   cin >> n >> p >> t ; 
   T = t ;
   FOR( i , n ) s += '0' , ans += '0' ; 
   
   while( t -- ){
   	 solve() ;
   }

}

• Subtask 0: 0 / 0
• Subtask 1: 0 / 10
• Subtask 2: 26.949999996000003 / 90