Submission #1065647

#	Time	Username	Problem	Language	Result	Execution time	Memory
1065647		EkinOnal	Zamjena (COCI18_zamjena)	C++17	70 / 70	166 ms	12368 KiB

zamjena

//#pragma GCC optimize("O3,unroll-loops,Ofast")
//#pragma GCC target("avx2,bmi,bmi2,popcnt,lzcnt")
#include <bits/stdc++.h>
//#include <ext/pb_ds/assoc_container.hpp>
//#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
//using namespace __gnu_pbds;
 
#define MAX 200007
#define pb push_back
#define mp make_pair 
#define int long long
#define f first
#define s second
#define vi vector<int>
#define pii pair<int,int>
#define si set<int>
#define vpii vector<pair<int,int>> 
const int mod = 1e9+7;
const int INF = 1e18;
// myMap.begin()->first :  key
// myMap.begin()->second : value
 
int epow(int a,int b){int ans=1;while(b){if(b&1) ans*=a;a*=a;;b>>=1;}return ans;}
int gcd(int a,int b) {if(a<b)swap(a,b);while(b){int tmp=b;b=a%b;a=tmp;}return a;}
int mul(int a,int b){return ((a%mod)*(b%mod))%mod;}
int sum(int a,int b){return ((a%mod)+(b%mod))%mod;}
 
//typedef tree<pii,null_type,less<pii>,rb_tree_tag,tree_order_statistics_node_update>ordered_set;
map<string, string> par;
map<string, int> sz;
string find(string x){
	if(par[x]==x) return x;
	return par[x]=find(par[x]);
}
bool unite(string a,string b){
	a = find(a), b=find(b);
	if(a[0]<'a' && b[0]<'a') return a==b;
	if(a[0]<'a'){
		par[b]=a;
		sz[a]+=sz[b];
		return true;
	}
	else if(b[0]<'a'){
		par[a]=b;
		sz[b]+=sz[a];
		return true;
	}
	else if(a==b) return true;
	if(sz[a]<sz[b]) swap(a,b);

	sz[a]+=sz[b];
	par[b]=a;
	return true;
}


void solve(){
	int n; cin>>n;
 
	vector<string> a(n); for(int i=0;i<n;i++) {cin>>a[i];par[a[i]]=a[i];sz[a[i]]++;}
	vector<string> b(n); for(int i=0;i<n;i++) {cin>>b[i];par[b[i]]=b[i];sz[b[i]]++;}
 
 	for(int i=0;i<n;i++){
 		if(!unite(a[i],b[i])) {cout<<"NE\n";return;}
 	}
	cout<<"DA\n";
 
	return;
}
 
int32_t main() {
//	freopen("hayfeast.in", "r", stdin);
//	freopen("hayfeast.out", "w", stdout);
	ios_base::sync_with_stdio(0);cin.tie(0);   
 
    int t=1;
 //   cin >> t;
    while (t--) solve();
 
    return 0;
}

• Subtask 1: 14 / 14
• Subtask 2: 14 / 14
• Subtask 3: 14 / 14
• Subtask 4: 14 / 14
• Subtask 5: 14 / 14