Submission #1064216

#TimeUsernameProblemLanguageResultExecution timeMemory
1064216clementineCatfish Farm (IOI22_fish)C++17
100 / 100
120 ms54604 KiB
#include "fish.h" #include <bits/stdc++.h> #define MAX 500005 #define INF (ll)(1e16) using namespace std; typedef long long ll; int N, M; ll up[MAX], down[MAX], sum[MAX], in[MAX], out[MAX]; vector<ll> X, Y, W; vector<pair<int, ll> > pos[MAX]; long long max_weights(int n, int m, std::vector<int> x, std::vector<int> y, std::vector<int> w) { N = n, M = m; X.resize(M); Y.resize(N + M + 1); W.resize(M); for(ll i = 0; i < M; ++i) X[i] = x[i] + 1, Y[i] = y[i] + 1, W[i] = w[i]; for(ll i = 0; i < M; ++i) pos[X[i]].push_back({Y[i], W[i]}); for(ll i = 1; i <= N; ++i) pos[i].push_back({N + 1, 0}); for(ll i = 1; i <= N; ++i) sort(pos[i].begin(), pos[i].end()); ll cnt = 0; for(ll i = 1; i <= N; ++i) { sum[++cnt] = pos[i][0].second; in[i] = cnt; Y[cnt] = pos[i][0].first; for(ll j = 1; j < (ll)pos[i].size(); ++j) { ++cnt; sum[cnt] = sum[cnt - 1] + pos[i][j].second; Y[cnt] = pos[i][j].first; } out[i] = cnt; } for(ll i = 0; i <= N; ++i) up[i] = down[i] = -INF; up[0] = down[0] = 0; Y[0] = -1; for(ll x = 1; x <= N; ++x) { ll k = in[x - 1], mx = -INF, p = -1; for(ll i = in[x]; i <= out[x]; ++i) { while(k <= out[x - 1] && Y[k] < Y[i]) { mx = max(mx, up[k] - (k == in[x - 1] ? 0 : sum[k - 1])); p = k; ++k; } up[i] = max(up[i], mx + (p == -1 ? 0 : sum[p])); } k = out[x - 1], mx = -INF, p = out[x]; for(ll i = out[x]; i >= in[x]; --i) { while(k >= in[x - 1] && Y[k] > Y[i]) { while(p >= in[x] && Y[k] <= Y[p]) --p; mx = max(mx, max(down[k], up[k]) + sum[p]); --k; } down[i] = max(down[i], mx - (i == in[x] ? 0 : sum[i - 1])); if(k >= in[x - 1] && Y[k] == Y[i]) down[i] = max(down[i], max(down[k], up[k])); } if(x < 2) continue; k = in[x - 2], mx = -INF, p = in[x - 1]; ll p2 = -1; for(ll i = in[x]; i <= out[x]; ++i) { while(k <= out[x - 2] && Y[k] <= Y[i]) { mx = max(mx, max(up[k], down[k])); ++k; } while(p <= out[x - 1] && Y[p] < Y[i]) p2 = p++; up[i] = max(up[i], mx + (p2 == -1 ? 0 : sum[p2])); } k = out[x - 2], mx = -INF, p = out[x - 1]; for(ll i = out[x]; i >= in[x]; --i) { while(k >= in[x - 2] && Y[k] > Y[i]) { while(p >= in[x - 1] && Y[k] <= Y[p]) --p; mx = max(mx, max(up[k], down[k]) + (p == in[x - 1] - 1 ? 0 : sum[p])); --k; } up[i] = max(up[i], mx); } } ll ret = 0; for(ll i = 0; i <= N + M; ++i) ret = max(ret, max(up[i], down[i])); return ret; }
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