Submission #1064166

#	Time	Username	Problem	Language	Result	Execution time	Memory
1064166		ewirlan	Arranging Shoes (IOI19_shoes)	C++17	100 / 100	85 ms	19280 KiB

shoes

//
#ifndef __SIZEOF_INT128__
  #define __SIZEOF_INT128__
#endif
#pragma GCC optimize("Ofast")
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace chrono;
using namespace __gnu_pbds;
template <typename T> using oset =  tree<T, null_type, less_equal<T>, rb_tree_tag, tree_order_statistics_node_update>;
#define rep(i, p, k) for(int i(p); i < (k); ++i)
#define per(i, p, k) for(int i(p); i > (k); --i)
#define sz(x) (int)(x).size()
#define sc static_cast
typedef long long ll;
typedef long double ld;
typedef unsigned int uint;
typedef unsigned long long ull;
typedef __int128_t lll;
//#define int ll
template <typename T = int> using par = std::pair <T, T>;
#define fi first
#define se second
#define test int _number_of_tests(in()); while(_number_of_tests--)
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
#define pb emplace_back
struct Timer {
    string name{""};
    time_point<high_resolution_clock> end, start{high_resolution_clock::now()};
    duration<float, std::milli> dur;
    Timer() = default;
    Timer(string nm): name(nm) {}
    ~Timer() {
        end = high_resolution_clock::now(); dur= end - start;
        cout << "@" << name << "> " << dur.count() << " ms" << '\n';
    }
};
template <typename T = int> inline T in()
{
    static T x;
    std::cin >> x;
    return x;
}
std::string yn(bool b)
{
    if(b) return "YES\n";
    else return "NO\n";
}
template <typename F, typename S> std::ostream& operator<<(std::ostream& out, const std::pair <F, S>& par);
template <typename T> std::ostream& operator<< (std::ostream& out, const std::vector <T>& wek)
{
    for(const auto& i : wek)out << i << ' ';
    return out;
}
template <typename F, typename S> std::ostream& operator<<(std::ostream& out, const std::pair <F, S>& par)
{
    out << '{'<<par.first<<", "<<par.second<<"}";
    return out;
}
#define show(x) cerr << #x << " = " << x << '\n';
constexpr int Opol = 1<<19;
int tre[2*Opol];
void add(int g, int c){
    g += Opol;
    while(g){
        tre[g] += c;
        g /= 2;
    }
}
int sum(int a, int b){
    a += Opol-1;
    b += Opol+1;
    int s(0);
    while(a+1 != b){
        if(a%2 == 0)s += tre[a+1];
        if(b%2 == 1)s += tre[b-1];
        a /= 2; b /= 2;
    }
    return s;
}
constexpr int maxn = 1e5 + 3;
vector <int> pol[maxn], por[maxn];
int parr[maxn*4];
bool uj[maxn*4];
ll count_swaps(vector <int> s)
{
    int n(sz(s)/2);
    int g(0);
    for(auto i: s){
        ++g;
        if(i > 0)++g;
        if(i < 0)pol[-i].pb(g);
        else por[i].pb(g);
        add(g, +1);
        if(i < 0)++g;
    }
    rep(i, 1, n+1){
        sort(all(pol[i]));
        sort(all(por[i]));
        rep(j, 0, sz(pol[i])){
            parr[pol[i][j]] = por[i][j];
            parr[por[i][j]] = pol[i][j];
            uj[pol[i][j]] = 1;
        }
    }
    ll o(0);
    rep(i, 1, n*4+1)if(parr[i]){
        int a(i), b(parr[i]);
        parr[a] = parr[b] = 0;
        if(uj[a])++a;
        else --a;
        o += sum(a+1, b-1);
        add(a, +1);
        add(b, -1);
    }
    return o;

}

• Subtask 1: 10 / 10
• Subtask 2: 20 / 20
• Subtask 3: 20 / 20
• Subtask 4: 15 / 15
• Subtask 5: 20 / 20
• Subtask 6: 15 / 15