Submission #1063930

#	Time	Username	Problem	Language	Result	Execution time	Memory
1063930		thinknoexit	Alice, Bob, and Circuit (APIO23_abc)	C++17	62 / 100	57 ms	9972 KiB

abc

#include "abc.h"
#include<bits/stdc++.h>
using namespace std;
using ll = long long;

// you may find the definitions useful
const int OP_ZERO = 0;  // f(OP_ZERO,    x0, x1) = 0
const int OP_NOR = 1;  // f(OP_NOR,     x0, x1) = !(x0 || x1)
const int OP_GREATER = 2;  // f(OP_GREATER, x0, x1) = (x0 > x1)
const int OP_NOT_X1 = 3;  // f(OP_NOT_X1,  x0, x1) = !x1
const int OP_LESS = 4;  // f(OP_LESS,    x0, x1) = (x0 < x1)
const int OP_NOT_X0 = 5;  // f(OP_NOT_X0,  x0, x1) = !x0
const int OP_XOR = 6;  // f(OP_XOR,     x0, x1) = (x0 ^ x1)
const int OP_NAND = 7;  // f(OP_NAND,    x0, x1) = !(x0 && x1)
const int OP_AND = 8;  // f(OP_AND,     x0, x1) = (x0 && x1)
const int OP_EQUAL = 9;  // f(OP_EQUAL,   x0, x1) = (x0 == x1)
const int OP_X0 = 10; // f(OP_X0,      x0, x1) = x0
const int OP_GEQ = 11; // f(OP_GEQ,     x0, x1) = (x0 >= x1)
const int OP_X1 = 12; // f(OP_X1,      x0, x1) = x1
const int OP_LEQ = 13; // f(OP_LEQ,     x0, x1) = (x0 <= x1)
const int OP_OR = 14; // f(OP_OR,      x0, x1) = (x0 || x1)
const int OP_ONE = 15; // f(OP_ONE,     x0, x1) = 1

int lexico(const char s[]) {
    int len = strlen(s);
    int res = 0;
    for (int j = 0;j < len;j++) {
        res = res * 27 + s[j] - 'a' + 1;
    }
    for (int j = 0;j < 4 - len;j++) res *= 27;
    return res;
}
// Alice (returns la)
int alice(
    const int n,
    const char names[][5],
    const unsigned short numbers[],
    bool outputs_alice[]
) {
    vector<int> rnk(n);
    vector<pair<int, int>> v;
    for (int i = 0;i < n;i++) {
        rnk[i] = lexico(names[i]);
        v.push_back({ rnk[i], i });
    }
    sort(v.begin(), v.end());
    vector<int> ord(n);
    for (int i = 0;i < n;i++) {
        ord[v[i].second] = i;
    }
    for (int i = 0;i < n;i++) {
        for (int j = 0;j < 16;j++)
            outputs_alice[16 * i + j] = (numbers[v[i].second] >> j) & 1;
    }
    int sz = 16 * n;
    // sort by lexicography order use 5 bit
    for (int i = 0;i < n;i++) {
        for (int j = 0;j < n;j++) {
            outputs_alice[sz++] = (j == ord[i]);
        }
    }
    return sz; // 16 * n + n * n
}


// Bob (returns lb)
int bob(
    const int m,
    const char senders[][5],
    const char recipients[][5],
    bool outputs_bob[]
) {
    vector<int> r1(m), r2(m);
    set<int> s;
    for (int i = 0;i < m;i++) {
        r1[i] = lexico(senders[i]);
        r2[i] = lexico(recipients[i]);
        s.insert(r1[i]), s.insert(r2[i]);
    }
    int n = s.size();
    vector<int> v;
    vector<vector<bool>> adj(n, vector<bool>(n, false));
    for (auto& x : s) v.push_back(x);
    for (int i = 0;i < m;i++) {
        int o1 = lower_bound(v.begin(), v.end(), r1[i]) - v.begin();
        int o2 = lower_bound(v.begin(), v.end(), r2[i]) - v.begin();
        adj[o2][o1] = 1;
    }
    for (int i = 0;i < n;i++) {
        for (int j = 0;j < n;j++) {
            outputs_bob[i * n + j] = adj[i][j];
        }
    }
    return n * n; // n * n
}


// Circuit (return l >= la + lb)
int circuit(
    const int la,
    const int lb,
    int operations[],
    int operands[][2],
    int outputs_circuit[][16]
) {
    int sz = la + lb;
    int n = (la - lb) / 16;
    // make one and zero
    operations[sz] = OP_ZERO, operands[sz][0] = operands[sz][1] = 0;
    const int ZERO = sz++;
    // initialize
    auto op = [&](int o, int a, int b) {
        operations[sz] = o;
        operands[sz][0] = a;
        operands[sz][1] = b;
        return sz++;};
    auto sum = [&](int a[], int b[], int c[]) {
        vector<int> s(16, 0);
        c[0] = op(OP_XOR, a[0], b[0]);
        s[0] = op(OP_AND, a[0], b[0]);
        for (int j = 1;j < 16;j++) {
            c[j] = op(OP_XOR, s[j - 1], op(OP_XOR, a[j], b[j]));
            s[j] = op(OP_AND, op(OP_OR, s[j - 1], a[j]),
                op(OP_AND, op(OP_OR, s[j - 1], b[j]), op(OP_OR, a[j], b[j])));
        }};
    //----------------
    int tp[16] = {}, t[16] = {}, cand[n][16] = {};
    for (int i = 0;i < n;i++) for (int j = 0;j < 16;j++) {
        outputs_circuit[i][j] = cand[i][j] = ZERO;
    }
    for (int i = 0;i < n;i++) {
        for (int j = 0;j < n;j++) {
            for (int k = 0;k < 16;k++) t[k] = op(OP_AND, la + i * n + j, j * 16 + k);
            sum(cand[i], t, tp);
            for (int k = 0;k < 16;k++) cand[i][k] = tp[k];
        }
    }
    for (int i = 0;i < n;i++) {
        for (int j = 0;j < n;j++) {
            for (int k = 0;k < 16;k++) t[k] = op(OP_AND, 16 * n + i * n + j, cand[j][k]);
            sum(outputs_circuit[i], t, tp);
            for (int k = 0;k < 16;k++) outputs_circuit[i][k] = tp[k];
        }
    }
    return sz;
}

• Subtask 1: 4 / 4
• Subtask 2: 4 / 4
• Subtask 3: 0 / 4
• Subtask 4: 24 / 24
• Subtask 5: 24 / 24
• Subtask 6: 6 / 6
• Subtask 7: 0 / 18
• Subtask 8: 0 / 10
• Subtask 9: 0 / 6