Submission #1061734

#	Time	Username	Problem	Language	Result	Execution time	Memory
1061734		VMaksimoski008	K blocks (IZhO14_blocks)	C++17	53 / 100	1048 ms	42372 KiB

blocks

#include <bits/stdc++.h>
using namespace std;

using ll = long long;
using pii = pair<int, int>;
using pll = pair<ll, ll>;

#pragma GCC optimize("O3,unroll-loops")
#pragma GCC target("avx,bmi,bmi2,lzcnt,popcnt")

const int mod = 1e9 + 7;
const int LOG = 20;
const int maxn = 1e5 + 5;

struct SegTree {
    int n;
    vector<ll> tree, lazy;
 
    SegTree(int _n) : n(_n), tree(4*_n+5), lazy(4*_n+5) {}
 
    void push(int u, int tl, int tr) {
        if(!lazy[u]) return ;
        tree[u] += lazy[u];
 
        if(tl != tr) {
            lazy[2*u] += lazy[u];
            lazy[2*u+1] += lazy[u];
        }
 
        lazy[u] = 0;
    }
 
    void update(int u, int tl, int tr, int l, int r, ll v) {
        push(u, tl, tr);
        if(tl > tr || l > tr || tl > r) return ;
 
        if(l <= tl && tr <= r) {
            lazy[u] += v;
            push(u, tl, tr);
            return ;
        }
 
        int tm = (tl + tr) / 2;
        update(2*u, tl, tm, l, r, v);
        update(2*u+1, tm+1, tr, l, r, v);
        tree[u] = min(tree[2*u], tree[2*u+1]);
    }
 
    ll query(int u, int tl, int tr, int l, int r) {
        if(tl > tr || l > tr || tl > r) return 1e12;
        push(u, tl, tr);
        if(l <= tl && tr <= r) return tree[u];
        int tm = (tl + tr) / 2;
        return min(query(2*u, tl, tm, l, r), query(2*u+1, tm+1, tr, l, r));
    }
 
    void update(int l, int r, ll v) { update(1, 0, n-1, l, r, v); }
    ll query(int l, int r) { return query(1, 0, n-1, l, r); }
};

ll dp[maxn][105], v[maxn];

signed main() {
    ios_base::sync_with_stdio(false);
    cout.tie(0); cin.tie(0);

    int n, k;
    cin >> n >> k;

    for(int i=0; i<=n; i++)
        for(int j=0; j<=k; j++) dp[i][j] = 1e9;
    for(int i=1; i<=n; i++) cin >> v[i];
    dp[0][0] = 0;

    ll mx = 0;
    for(int i=1; i<=n; i++) {
        mx = max(mx, v[i]);
        dp[i][1] = mx;
    }

    for(int j=2; j<=k; j++) {
        SegTree tree(n+1);
        vector<pii> st; st.push_back({ 1e9, 0 });
        int SZ = 1;
        for(int i=1; i<=n; i++) {
            int last = st.back().second;
            while(SZ && st.back().first <= v[i]) {
                if(SZ > 1) tree.update(st[SZ-2].second+1, st[SZ-1].second, v[i]-st.back().first);
                st.pop_back();
                SZ--;
            }

            st.push_back({ v[i], i }); SZ++;
            tree.update(last+1, st.back().second, v[i]);
            tree.update(i, i, dp[i-1][j-1]);
            dp[i][j] = tree.query(1, i);
        }
    }

    cout << dp[n][k] << '\n';
    return 0;
}

• Subtask 1: 14 / 14
• Subtask 2: 18 / 18
• Subtask 3: 21 / 21
• Subtask 4: 0 / 47