Submission #1058260

#TimeUsernameProblemLanguageResultExecution timeMemory
1058260SzymonKrzywdaCircle Passing (EGOI24_circlepassing)C++17
100 / 100
187 ms6596 KiB
#include <bits/stdc++.h> using namespace std; int n; int odl(int a, int b){ int wynik=abs(a-b); wynik = min(wynik, (2*n)-max(a,b)+min(a,b)); return wynik; } int main() { int m,q,a,b; cin >> n >> m >> q; vector<int> pary(0); for (int i=0; i<m; i++){ cin >> a; pary.push_back(a); pary.push_back(a+n); } sort(pary.begin(),pary.end()); /* //for (auto [i_1,i_2] : pary) cout << i_1 << " " << i_2 << endl; //liczymy pierwszy na lewo int akt_para = 1; int akt_idx = pary[0]; vector<int> lewo(2*n); for (int i=0; i<2*n; i++){ if (akt_para < pary.size() && pary[akt_para]==akt_idx){ akt_para++; } //cout << akt_idx << endl; lewo[akt_idx] = pary[akt_para-1]; cout << akt_idx << " " << lewo[akt_idx] << endl; akt_idx = (akt_idx+1)%(2*n); } //Liczymy pierwszy na prawo akt_para = (2*m)-2; akt_idx = pary[(2*m)-1]; vector<int> prawo(2*n); for (int i=0; i<2*n; i++){ //cout << "DUPA " << (akt_idx-1+(2*n))%(2*n) << " " << akt_idx << endl; if (akt_para >=0 && pary[akt_para]==akt_idx){ akt_para--; } prawo[akt_idx] = pary[akt_para+1]; cout << akt_idx << " " << prawo[akt_idx] << endl; akt_idx = (akt_idx-1+(2*n))%(2*n); }*/ for (int i=0; i<q; i++){ cin >> a >> b; int lewo,prawo; //prawo int lewo_=0,prawo_=(2*m)-1; while (lewo_<prawo_){ int mid = (lewo_+prawo_)/2; //cout << lewo_ << " " << prawo_ << " " << mid << endl; if (pary[mid]>=a) prawo_=mid; else lewo_ = mid+1; } if (pary[lewo_]>=a) prawo = pary[lewo_]; else prawo = pary[0]; //lewo lewo_=0,prawo_=(2*m)-1; while (lewo_<prawo_){ int mid = (lewo_+prawo_+1)/2; //cout << "TU: " << lewo_ << " " << prawo_ << " " << mid << endl; if (pary[mid]<=a) lewo_=mid; else prawo_ = mid-1; } //cout << pary[lewo_] << " " << lewo_ << endl; if (pary[lewo_]<=a) lewo = pary[lewo_]; else lewo = pary[(2*m)-1]; //cout << a << " " << b<< " " << lewo << " " << prawo << endl; int wynik = odl(a,b); wynik = min(wynik, 1+odl(a,prawo) + odl(((prawo+n)%(2*n)), b)); wynik = min(wynik, 1+odl(a,lewo) + odl(((lewo+n)%(2*n)), b)); cout << wynik << endl; } return 0; }
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