Submission #1058005

#TimeUsernameProblemLanguageResultExecution timeMemory
1058005caterpillowFun Tour (APIO20_fun)C++17
26 / 100
184 ms524288 KiB
#include <bits/stdc++.h> #include <string> using namespace std; using db = long double; using ll = long long; using pl = pair<ll, ll>; using pi = pair<int, int>; #define vt vector #define f first #define s second #define pb push_back #define all(x) x.begin(), x.end() #define size(x) ((int) (x).size()) #define FOR(i, a, b) for (int i = (a); i < (b); i++) #define ROF(i, a, b) for (int i = (b) - 1; i >= (a); i--) #define F0R(i, b) FOR (i, 0, b) #define endl '\n' const ll INF = 1e18; const int inf = 1e9; template<typename... Args> // tuples ostream& operator<<(ostream& os, tuple<Args...> t) { apply([&](Args... args) { string dlm = "{"; ((os << dlm << args, dlm = ", "), ...); }, t); return os << "}"; } template<typename T, typename V> // pairs ostream& operator<<(ostream& os, pair<T, V> p) { return os << "{" << p.f << ", " << p.s << "}"; } template<class T, class = decltype(begin(declval<T>()))> // iterables typename enable_if<!is_same<T, string>::value, ostream&>::type operator<<(ostream& os, const T& v) { string dlm = "{"; for (auto& i : v) os << dlm << i, dlm = ", "; return os << "}"; } template <typename T, typename... V> void printer(string pfx, const char *names, T&& head, V&& ...tail) { int i = 0; while (names[i] && names[i] != ',') i++; constexpr bool is_str = is_same_v<decay_t<T>, const char*>; if (is_str) cerr << " " << head; else cerr << pfx, cerr.write(names, i) << " = " << head; if constexpr (sizeof...(tail)) printer(is_str ? "" : ",", names + i + 1, tail...); else cerr << endl; } #ifdef LOCAL #define dbg(...) printer(to_string(__LINE__) + ": ", #__VA_ARGS__, __VA_ARGS__) #else #define dbg(x...) #define cerr if (0) std::cerr #endif #include "fun.h" /* we can query distance and rooted subtree size subtask 1 and 2: n^2 subtask 3: perfect binary tree, rooted at 0 with segtree indexing (kinda) subtask 4: im pretty sure this is meant to be a star graph repeatedly taking the diameter will give a valid tour trust */ int n, q; vt<int> createFunTour(int N, int Q) { n = N; q = Q; vt<vt<int>> dist(n, vt<int>(n)); F0R (i, n) { FOR (j, i + 1, n) { dist[i][j] = dist[j][i] = hoursRequired(i, j); } } int u = 0, v = 0; F0R (w, n) { if (dist[u][w] > dist[u][v]) v = w; } swap(u, v); // repeatedly find diameter, starting from u vt<bool> done(n); vt<int> out {u}; done[u] = true; F0R (i, n - 1) { v = u; F0R (w, n) { if (done[w]) continue; if (dist[u][w] > dist[u][v]) v = w; } out.pb(v); u = v; done[v] = true; } dbg(out); return out; }
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