Submission #1056155

#TimeUsernameProblemLanguageResultExecution timeMemory
1056155MuhammetRoad Closures (APIO21_roads)C++17
5 / 100
2051 ms8644 KiB
#include <bits/stdc++.h>
#include "roads.h"

using namespace std;

#define ll long long
#define ff first
#define ss second

vector<ll> minimum_closure_costs(int n, vector<int> u, vector<int> u1, vector<int> w) {
    vector <pair<ll,pair<ll,ll>>> v;
    ll s = 0;
    bool tr = 0;
    for(int i = 0; i < n-1; i++){
        v.push_back({w[i],{u[i],u1[i]}});
        if(u1[i] != u[i]+1) tr = 1;
        s += w[i];
    }
    vector <ll> p(n), p1(n), v1;
    for(int i = 0; i < n; i++){
        p1[u[i]]++;
        p1[u1[i]]++;
    }
    sort(v.rbegin(), v.rend());
    if(*max_element(u.begin(), u.end()) == 0){
        ll s2 = s;
        v1.push_back(s);
        for(int i = 0; i < n-1; i++){
            s2 -= (v[i].ff);
            v1.push_back(s2);
        }
        return v1;
    }
    if(tr == 0){
        v1.push_back(s);
        if(n >= 3){
            vector <ll> p1(n), p2(n);
            for(int i = 0; i < n-1; i++){
                if(i > 0) p1[i] = p1[i-1], p2[i] = p2[i-1];
                if(i % 2 == 0) p2[i] += w[i];
                else p1[i] += w[i];
            }
            ll mx = max(p1[n-2],p2[n-2]);
            for(int i = 0; i < n-2; i++){
                mx = max(mx,p1[i]+p2[n-2]-p2[i]);
                mx = max(mx,p2[i]+p1[n-2]-p1[i]);
            }
            v1.push_back(s-mx);
            for(int i = 2; i < n-1; i++) v1.push_back(0);
            return v1;
        }
    }
    for(int i = 0; i < n; i++){
        // p = p1;
        p.clear();
        ll s1 = s;
        for(auto j : v){
            if(p[j.ss.ff] < i and p[j.ss.ss] < i){
                s1 -= j.ff;
                p[j.ss.ff]++;
                p[j.ss.ss]++;
            }
        }

        v1.push_back(s1);
    }
    return v1;
}
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