Submission #1055429

#	Time	Username	Problem	Language	Result	Execution time	Memory
1055429		vjudge1	Pipes (CEOI15_pipes)	C++17	20 / 100	166 ms	12884 KiB

pipes

#include <bits/stdc++.h>
using namespace std;

#pragma GCC optimize("O3")
#define endl '\n'
#define db double
#define ll __int128
//#define int long long
#define pb push_back
#define fs first
#define sd second
#define Mod long(1e9 + 7)
#define all(x) x.begin(), x.end()
#define unvisited long(-1)
#define Eps double(1e-9)
#define _for(i, n) for(int i = 0; i < (n); i++)
#define dbg(x) cout << #x ": " << x << endl;

const int Max = 1e4 + 7, Inf = 1e16 + 7;

void print(bool x) { cout << (x ? "YES" : "NO") << endl; }

string tostring (__int128 x)
{
    string ans = "";
    while(x > 0)
    {
        ans += (x % 10 + '0');
        x /= 10;
    }
    reverse(all(ans));
    return ans;
}

bitset <Max> v[Max];
vector <int> l, s; int idx, n;

void dfs(int node, int parent)
{  
    l[node] = s[node] = idx; idx++; 

    for(int u = 1; u <= n; u++)if(u != parent && v[node][u] == 1){
        if(s[u] == 0){
            dfs(u, node); 
            if(l[u] > s[node]){
                cout << node << " " << u << endl;
            }
            l[node] = min(l[node], l[u]); 
        }
        else l[node] = min(l[node], s[u]); 
    }
}

void solve()
{
    int m; cin >> n >> m; 
    l.assign(n+1, 0); s.assign(n+1, 0);
    idx = 1; 
    for(int i = 0; i < m; i++){
        int a, b; cin >> a >> b; 
        v[a][b] = v[b][a] = 1;
    }

    for(int i = 1; i <= n; i++) if(s[i] == 0){
        dfs(i, 0); 
    }
}

int32_t main()
{
    ios_base::sync_with_stdio(0);
    cin.tie(0);

    int Q = 1; //cin >> Q;

    while (Q--)
    {
        solve();
    }

    return 0;
}

Compilation message (stderr)

pipes.cpp:19:37: warning: overflow in conversion from 'double' to 'int' changes value from '1.0000000000000008e+16' to '2147483647' [-Woverflow]
   19 | const int Max = 1e4 + 7, Inf = 1e16 + 7;
      |                                ~~~~~^~~

• Subtask 1: 0 / 10
• Subtask 2: 0 / 10
• Subtask 3: 10 / 10
• Subtask 4: 10 / 10
• Subtask 5: 0 / 10
• Subtask 6: 0 / 10
• Subtask 7: 0 / 10
• Subtask 8: 0 / 10
• Subtask 9: 0 / 10
• Subtask 10: 0 / 10