Submission #1054558

#	Time	Username	Problem	Language	Result	Execution time	Memory
1054558		pan	Carnival (CEOI14_carnival)	C++17	100 / 100	9 ms	512 KiB

carnival

#include <bits/stdc++.h>
//#include "bits_stdc++.h"
//#include <ext/pb_ds/assoc_container.hpp>
//#include <ext/pb_ds/tree_policy.hpp>
#define endl '\n'
#define f first
#define s second
#define pb push_back
#define mp make_pair
#define lb lower_bound
#define ub upper_bound
#define input(x) scanf("%lld", &x);
#define input2(x, y) scanf("%lld%lld", &x, &y);
#define input3(x, y, z) scanf("%lld%lld%lld", &x, &y, &z);
#define input4(x, y, z, a) scanf("%lld%lld%lld%lld", &x, &y, &z, &a);
#define print(x, y) printf("%lld%c", x, y);
#define show(x) cerr << #x << " is " << x << endl;
#define show2(x,y) cerr << #x << " is " << x << " " << #y << " is " << y << endl;
#define show3(x,y,z) cerr << #x << " is " << x << " " << #y << " is " << y << " " << #z << " is " << z << endl;
#define all(x) x.begin(), x.end()
#define discretize(x) sort(x.begin(), x.end()); x.erase(unique(x.begin(), x.end()), x.end());
#define FOR(i, x, n) for (ll i =x; i<=n; ++i) 
#define RFOR(i, x, n) for (ll i =x; i>=n; --i) 
using namespace std;
//using namespace __gnu_pbds;
//#define ordered_set tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update>
//#define ordered_multiset tree<int, null_type, less_equal<int>, rb_tree_tag, tree_order_statistics_node_update>
typedef long long ll;
typedef long double ld;
typedef pair<ld, ll> pd;
typedef pair<string, ll> psl;
typedef pair<ll, ll> pi;
typedef pair<ll, pi> pii;
typedef pair<pi, pi> piii;


int main()
{
	ll n;
	cin >> n;
	vector<ll> type(n, -1);
	vector<ll> cnt(n, 1);
	ll c=0;
	for (ll i=0; i<n; ++i)
	{
		//show(i);
		ll lo = -1, hi = i;
		while (lo!=hi)
		{
			ll mid = (lo+hi+1)/2, ret, counter = 0;
			cout << i - mid + 1;
			for (ll j=i; j>=mid ;--j) {counter += cnt[j]; cout << ' ' << j+1;}
			cout << endl;
			cin >> ret;
			if (counter > ret) lo = mid;
			else hi = mid-1;
		}
		//show(lo);
		if (lo==-1) {type[i] = ++c;}
		else {type[i] = type[lo]; cnt[lo] = 0;}
		//show(type[i]);
	}
	cout << 0;
	for (ll i=0; i<n; ++i) cout << ' ' << type[i];
	cout << endl;
	return 0;
}

• Subtask 1: 20 / 20
• Subtask 2: 20 / 20
• Subtask 3: 20 / 20
• Subtask 4: 20 / 20
• Subtask 5: 20 / 20