Submission #1054355

#	Time	Username	Problem	Language	Result	Execution time	Memory
1054355		Harold	Palembang Bridges (APIO15_bridge)	C++14	22 / 100	25 ms	3272 KiB

bridge

#include<bits/stdc++.h>

using namespace std;

#define ll long long

int main() {
    ios_base::sync_with_stdio(0);
    cin.tie(0);
    /*int k, n;
    cin >> k >> n;
    vector<pair<int, int>> a, p;
    int res = 0;
    for(int i = 0; i < n; i++) {
        char c1, c2;
        int a1, a2;
        cin >> c1 >> a1 >> c2 >> a2;
        if(c1 == c2) {
            res += abs(a1-a2);
        }
        else {
            a.push_back({a1, a2});
        }
    }
    // incorrect when k = 2 couse need to choose
    sort(a.begin(), a.end());
    for(auto i: a) {
        pair<int, int> cur = {i.first, i.second};
        if(p.empty()) {
            p.push_back(cur);
            continue;
        }
        if(p.back().second >= cur.first) {
            p.back() = {cur.first, p.back().second};
        }
        else {
            p.push_back(cur);
        }
    }
    int i = 0; // point to cur element in a
    int j = 0; // point to element in p
    int cross = 0;
    while(k > 0 && j < p.size()) {
        cross = p[j].second;
        while(i < a.size() && a[i].first <= cross) {
            res += abs(a[i].second-a[i].first);
            i++;
        }
        j++;
        k--;
    }

    while(i < a.size()) {
        res += abs(a[i].second-a[i].first) + 2*abs(cross-a[i].first);
        i++;
    }

    cout << res+a.size() << endl;*/

    int k, n;
    cin >> k >> n;
    vector<int> a;
    vector<pair<ll, ll>> p;
    ll res = 0;
    for(int i = 0; i < n; i++) {
        char c1, c2;
        ll a1, a2;
        cin >> c1 >> a1 >> c2 >> a2;
        if(c1 == c2) {
            res += abs(a1-a2);
        }
        else {
            a.push_back(a1);
            a.push_back(a2);
            p.push_back({a1, a2});
        }
    }
    sort(a.begin(), a.end());
    if(k == 1) {
        int m = a.size()/2;
        for(auto i: p) {
            res += abs(a[m]-i.first) + abs(a[m]-i.second)+1;
        }
    }
    else {
        // dist from middle should be as small as possible
        ll l = 0, r = 0;
        for(int i = 0; i < n; i++) {
            r += a[i];
        }
        ll cur = r;
        for(int i = 0; i < n; i++) {
            r -= a[i];
            l += a[i];
            cur = min(cur, r-l);
        }
        res += cur;
    }

    cout << res << "\n";

    return 0;
}

• Subtask 1: 8 / 8
• Subtask 2: 14 / 14
• Subtask 3: 0 / 9
• Subtask 4: 0 / 32
• Subtask 5: 0 / 37