This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
/*
* Author: Nonoze
* Created: Monday 12/08/2024
*/
#include <bits/stdc++.h>
using namespace std;
#ifndef _IN_LOCAL
#define dbg(...)
#endif
#define endl '\n'
#define endlfl '\n' << flush
#define quit(x) return (void)(cout << x << endl)
template<typename T> void read(T& x) { cin >> x;}
template<typename T1, typename T2> void read(pair<T1, T2>& p) { read(p.first), read(p.second);}
template<typename T> void read(vector<T>& v) { for (auto& x : v) read(x); }
template<typename T1, typename T2> void read(T1& x, T2& y) { read(x), read(y); }
template<typename T1, typename T2, typename T3> void read(T1& x, T2& y, T3& z) { read(x), read(y), read(z); }
template<typename T1, typename T2, typename T3, typename T4> void read(T1& x, T2& y, T3& z, T4& zz) { read(x), read(y), read(z), read(zz); }
template<typename T> void print(vector<T>& v) { for (auto& x : v) cout << x << ' '; cout << endl; }
#define sz(x) (int)(x.size())
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
#define pb push_back
#define mp make_pair
#define fi first
#define se second
#define cmin(a, b) a = min(a, b)
#define cmax(a, b) a = max(a, b)
#define int long long
const int inf = numeric_limits<int>::max() / 4;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
const int MOD = 1e9+7, LOG=25;
void solve();
signed main() {
ios::sync_with_stdio(0);
cin.tie(0);
int tt=1;
// cin >> tt;
while(tt--) solve();
return 0;
}
int n, k, m, q;
vector<int> a;
string s;
int calc(int x) {
int ans=0;
for (int i=0; i<n; i++) {
int act=abs(a[i]-x)%k;
cmin(act, k-act);
cmax(ans, act);
}
return ans;
}
// 0, 6, 5, 1, 5, 1
// 24 22 21 25 29 17
void solve() {
read(n, k);
a.clear(), a.resize(n); read(a);
for (auto &u: a) u%=k;
multiset<int> st;
for (int i=0; i<n; i++) st.insert(a[i]);
int ans=k, cnt=0;
while (cnt++<n) {
int x=*st.begin(), y=*st.rbegin();
cmin(ans, (y-x+1)/2);
st.erase(st.begin());
st.insert(x+k);
}
quit(ans);
}
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