Submission #1050899

#	Time	Username	Problem	Language	Result	Execution time	Memory
1050899		Blagoj	Dungeons Game (IOI21_dungeons)	C++17	100 / 100	4304 ms	1792936 KiB

dungeons

#include <bits/stdc++.h>
#include "dungeons.h"

#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("Ofast,unroll-loops")

using namespace std;

#define ll long long
#define inf 1e17

const int mxn = 4e5 + 10, LOG1 = 25, LOG2 = 9, BASE = 8;
//						  steps,     pwr
int n;
vector<int> s, p, w, l;
int go[mxn][LOG1][LOG2];
ll gain[mxn][LOG1][LOG2], lim[mxn][LOG1][LOG2];
ll F[LOG2];

void init(int _n, vector<int> _s, vector<int> _p, vector<int> _w, vector<int> _l) {
	F[0] = 1;
	for (int i = 1; i < LOG2; i++) F[i] = F[i - 1] * BASE;
	n = _n, s = _s, p = _p, w = _w, l = _l;
	for (int pwr = 0; pwr < LOG2; pwr++) {
		for (int i = 0; i < n; i++) {
			if (F[pwr] >= s[i]) {
				if (w[i] == n) go[i][0][pwr] = -1;
				else {
					go[i][0][pwr] = w[i];
					gain[i][0][pwr] = s[i];
					lim[i][0][pwr] = inf;
				}
			}
			else {
				if (l[i] == n) go[i][0][pwr] = -1;
				else {
					go[i][0][pwr] = l[i];
					gain[i][0][pwr] = p[i];
					lim[i][0][pwr] = s[i];
				}
			}
		}
	}	
	for (int pwr = 0; pwr < LOG2; pwr++) {
		for (int steps = 1; steps < LOG1; steps++) {
			for (int i = 0; i < n; i++) {
				int nxt = go[i][steps - 1][pwr];
				if (go[i][steps - 1][pwr] == -1 || go[nxt][steps - 1][pwr] == -1) go[i][steps][pwr] = -1;
				else {
					go[i][steps][pwr] = go[nxt][steps - 1][pwr];
					gain[i][steps][pwr] = gain[i][steps - 1][pwr] + gain[nxt][steps - 1][pwr];
					lim[i][steps][pwr] = min(lim[i][steps - 1][pwr], lim[nxt][steps - 1][pwr] - gain[i][steps - 1][pwr]);
				}
			}
		}
	}
}

ll simulate(int x, int z) {
	ll ans = z;
	int pwr = 0;
	while (x != n) { 
		while (pwr + 1 < LOG2 && F[pwr + 1] <= ans) pwr++;
		for (int i = LOG1 - 1; i >= 0; i--) {
			if (go[x][i][pwr] == -1) continue;
			if (ans >= lim[x][i][pwr]) continue;
			ans += gain[x][i][pwr];
			x = go[x][i][pwr];
		}
		if (ans >= s[x]) {
			ans += s[x];
			x = w[x];
		}
		else {
			ans += p[x];
			x = l[x];
		}
	}
	return ans;
}

• Subtask 1: 11 / 11
• Subtask 2: 26 / 26
• Subtask 3: 13 / 13
• Subtask 4: 12 / 12
• Subtask 5: 27 / 27
• Subtask 6: 11 / 11