Submission #1050502

#TimeUsernameProblemLanguageResultExecution timeMemory
1050502vjudge1Commuter Pass (JOI18_commuter_pass)C++17
15 / 100
101 ms15768 KiB
#include <bits/stdc++.h> //#include <ext/pb_ds/assoc_container.hpp> using namespace std; //using namespace __gnu_pbds; #define speed ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); #define russian setlocale(LC_ALL,"Russian_Russia.20866"); #define file freopen("onlyone.in", "r", stdin), freopen("onlyone.out", "w", stdout); #define ll long long //#define int long long #define ull unsigned long long #define ld long double #define pll pair<ll, ll> #define pii pair<int, int> #define all(s) s.begin(), s.end() #define pb push_back #define ins insert #define mp make_pair #define sz(x) x.size() #define F first #define S second #define lb lower_bound #define ub upper_bound #define mem(x) memset(x, 0, sizeof(x)) mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); const ll N = 100010; const ll M = 600000; const ll block = 316; const ll mod = 1e9 + 7; const ll P = 263; const ld pi = acos(-1); const ll inf = 1e9; ll add(ll a, ll b) { if(a + b < 0) return a + b + mod; if(a + b >= mod) return a + b - mod; return a + b; } ll sub(ll a, ll b) { return (a - b + mod) % mod; } ll mul(ll a, ll b) { return a * 1LL * b % mod; } ll binpow(ll a, ll n) { ll res = 1; while(n) { if (n & 1) res = mul(res, a); a = mul(a, a); n >>= 1; } return res; } ll inv(ll x) { return binpow(x, mod - 2); } int n, m, s, t, u, v; int p[N]; vector<pii> g[N]; ll dijikstra(int st, int en) { vector<ll> dist(n + 1, LLONG_MAX); dist[st] = 0LL; priority_queue<pair<ll, int>> q; q.push({0LL, st}); while(!q.empty()) { int v = q.top().S; ll d = -q.top().F; q.pop(); if(d > dist[v]) continue; for(auto to: g[v]) { if(dist[to.F] > dist[v] + to.S) { p[to.F] = v; dist[to.F] = dist[v] + to.S; q.push({-dist[to.F], to.F}); } } } return dist[en]; } void solve() { cin >> n >> m; cin >> s >> t; cin >> u >> v; while(m--) { int v1, v2, c; cin >> v1 >> v2 >> c; g[v1].pb({v2, c}); g[v2].pb({v1, c}); } dijikstra(s, t); int k = t; while(p[k] != 0) { for(int j = 0; j < (int)sz(g[k]); j++) { if(g[k][j].F == p[k]) { g[k][j].S = 0; break; } } for(int j = 0; j < (int)sz(g[p[k]]); j++) { if(g[p[k]][j].F == k) { g[p[k]][j].S = 0; break; } } k = p[k]; } cout << dijikstra(u, v) << '\n'; } signed main() { speed; //file int test = 1; //cin >> test; while(test--) { solve(); } }
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