Submission #1050501

#TimeUsernameProblemLanguageResultExecution timeMemory
1050501vjudge1Snake Escaping (JOI18_snake_escaping)C++17
75 / 100
2045 ms52540 KiB
#pragma GCC optimize("Ofast,unroll-loops,no-stack-protector,fast-math,inline") #include <bits/stdc++.h> #pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,lzcnt,mmx,abm,avx,avx2,fma") using namespace std; // using namespace __gnu_pbds; // typedef tree<pair<int,int>,null_type,less<pair<int,int>>,rb_tree_tag,tree_order_statistics_node_update> ordered_set; #define static_assert(...); #include <tr2/dynamic_bitset> using custom_bitset = tr2::dynamic_bitset<__uint128_t>; #define speed ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); #define int long long #define bigInt __int128 #define dl double long #define fl float #define all(s) s.begin(), s.end() #define pub push_back #define puf push_front #define pob pop_back #define pof pob_front #define ins insert #define F first #define S second #define len length const int N = 100010; const int M = 1010; const int LN = 131072; const int INF = 1000000000000000000; const int MOD = 1e9 + 7; const int BLOCK = 500; int binpow(int a, int b, int MOD) { int res = 1; while (b > 0) { if (b & 1) { res = res * a; res %= MOD; } a = a * a; a %= MOD; b >>= 1; } return res; } int MMI(int a, int MOD) { int ret = binpow(a, MOD - 2, MOD); return ret; } // int mdiv(int a, int b) { // int ret = a*MMI(b); // ret %= MOD; // return ret; // } int mmul(int a, int b) { int ret = (a % MOD) * (b % MOD); ret %= MOD; return ret; } int madd(int a, int b) { int ret = (a % MOD) + (b % MOD); ret %= MOD; return ret; } int msub(int a, int b) { int ret = (a % MOD) - (b % MOD); ret += MOD; ret %= MOD; return ret; } int GCD(int a, int b) { if (b == 0) { return a; } return GCD(b, a % b); } int LCM(int a, int b) { return a*b / GCD(a, b); } struct pqComp { bool operator()(const pair<int, int>& p1, const pair<int, int>& p2) const { return (p1.F < p2.F) || (p1.F == p2.F && p1.S < p2.S); } }; bool pCompF(pair<int, int>& p1, pair<int, int>& p2) { return p1.F < p2.F; } bool pCompS(pair<int, int>& p1, pair<int, int>& p2) { return p1.S < p2.S; } bool pCompFS(pair<int, int>& p1, pair<int, int>& p2) { return (p1.S < p2.S) || (p1.S == p2.S && p1.F < p2.F); } vector <pair<int, int>> DS {{1, 0}, {0, 1}};//{{0, -1}, {1, 0}, {0, 1}, {-1, 0}};//, {-1, -1}, {-1, 1}, {1, -1}, {1, 1}}; int n, q, a[11*N], sub[11*N], sup[11*N]; void solve() { cin >> n >> q; for (int i = 0; i < (1 << n); ++i) { char c; cin >> c; a[i] = (c - '0'); } for (int i = 0; i < (1 << n); ++i) { sub[i] = a[i]; sup[i] = a[i]; } for (int i = 0; i < n; ++i) { for (int mask = 0; mask < (1 << n); ++mask) { if (((mask >> i) & 1)) { sub[mask] += sub[mask - (1 << i)]; } } } for (int i = 0; i < n; ++i) { for (int mask = (1 << n) - 1; mask >= 0; --mask) { if (!((mask >> i) & 1)) { sup[mask] += sup[mask + (1 << i)]; } } } while (q--) { string s; cin >> s; map<char,int> cnt; for (char c: s) { ++cnt[c]; } reverse(all(s)); int mask = 0; map<char,vector<int>> v; for (int i = 0; i < n; ++i) { v[s[i]].pub(i); if (s[i] != '?') { mask += (1 << i)*(s[i] - '0'); } } int ans = 0; if (cnt['?'] <= 6) { for (int mask1 = 0; mask1 < (1 << cnt['?']); ++mask1) { int nmask = mask; for (int i = 0; i < cnt['?']; ++i) { if ((mask1 >> i) & 1) { nmask += (1 << v['?'][i]); } } ans += a[nmask]; } } else if (cnt['1'] <= 6) { for (int i: v['?']) { mask += (1 << i); } for (int mask1 = 0; mask1 < (1 << cnt['1']); ++mask1) { int nmask = mask; for (int i = 0; i < cnt['1']; ++i) { if ((mask1 >> i) & 1) { nmask -= (1 << v['1'][i]); } } if (__builtin_popcount(mask1) % 2) { ans -= sub[nmask]; } else { ans += sub[nmask]; } } } else { for (int mask1 = 0; mask1 < (1 << cnt['0']); ++mask1) { int nmask = mask; for (int i = 0; i < cnt['0']; ++i) { if ((mask1 >> i) & 1) { nmask += (1 << v['0'][i]); } } if (__builtin_popcount(mask1) % 2) { ans -= sup[nmask]; } else { ans += sup[nmask]; } } } cout << ans << '\n'; } } signed main() { speed; int T = 1; //cin >> T; while (T--) { solve(); } } /* НЕ ЗАХОДИТ РЕШЕНИЕ? 1) ПРОВЕРЬ НА ОЧЕВИДНЫЕ ОШИБКИ В КОДЕ 2) ПРОВЕРЬ НА ПЕРЕПОЛНЕНИЯ 3) УБЕДИСЬ В ПРАВИЛЬНОСТИ АЛГОРИТМА */
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