Submission #1049781

#	Time	Username	Problem	Language	Result	Execution time	Memory
1049781		vjudge1	Stove (JOI18_stove)	C++17	0 / 100	0 ms	348 KiB

stove

#include <bits/stdc++.h>
//#include <ext/pb_ds/assoc_container.hpp>
using namespace std;
//using namespace __gnu_pbds;

#define speed ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
#define russian setlocale(LC_ALL,"Russian_Russia.20866");
#define file freopen("onlyone.in", "r", stdin), freopen("onlyone.out", "w", stdout);
#define ll long long
#define ull unsigned long long
#define ld long double
#define pll pair<ll, ll>
#define pii pair<int, int>
#define all(s) s.begin(), s.end()
#define pb push_back
#define ins insert
#define mp make_pair
#define sz(x) x.size()
#define F first
#define S second
#define lb lower_bound
#define ub upper_bound
#define mem(x) memset(x, 0, sizeof(x))
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());

const ll N = 100010;
const ll M = 600000;
const ll block = 316;
const ll mod = 1e9 + 7;
const ll P = 263;
const ld pi = acos(-1);
const ll inf = 1e9;

ll add(ll a, ll b) {
    if(a + b < 0) return a + b + mod;
    if(a + b >= mod) return a + b - mod;
    return a + b;
}

ll sub(ll a, ll b) {
    return (a - b + mod) % mod;
}

ll mul(ll a, ll b) {
    return a * 1LL * b % mod;
}

ll binpow(ll a, ll n) {
    ll res = 1;
    while(n) {
        if (n & 1) res = mul(res, a);
        a = mul(a, a);
        n >>= 1;
    }
    return res;
}

ll inv(ll x) {
    return binpow(x, mod - 2);
}
ll n, k;
ll t[N];
bool check(ll x) {
    ll cnt = 0;
    ll lst = t[1];
    for(ll i = 2; i <= n; i++) {
        if(t[i] - lst + 1 > x) {
            cnt++;
            lst = t[i];
        }
    }
    return (cnt + 1 <= k);
}
void solve() {
    cin >> n >> k;
    for(ll i = 1; i <= n; i++) {
        cin >> t[i];
    }
    ll l = 0, r = 1e9 + 1;
    while(r > l + 1) {
        ll mid = (l + r) / 2;
        if(check(mid)) r = mid;
        else l = mid;
    }
    ll ans = 0LL;
    ll lst = t[1];
    for(ll i = 2; i <= n; i++) {
        if(t[i] - lst + 1 > r) {
            ans += (t[i - 1] - lst + 1LL);
            lst = t[i];
        }
    }
    ans += (t[n] - lst + 1LL);
    cout << ans << '\n';
}
signed main() {
    speed;
    //file
    int test = 1;
    //cin >> test;
    while(test--) {
        solve();
    }
}

• Subtask 1: 0 / 20
• Subtask 2: 0 / 30
• Subtask 3: 0 / 50