Submission #1045889

#TimeUsernameProblemLanguageResultExecution timeMemory
1045889TsovakPetrol stations (CEOI24_stations)C++17
18 / 100
3348 ms25684 KiB
// -------------------- Includes -------------------- // #define _CRT_SECURE_NO_WARNINGS #define _USE_MATH_DEFINES #include <iostream> #include <iomanip> #include <cstdio> #include <stdio.h> #include <cstdlib> #include <stdlib.h> #include <array> #include <string> #include <cstring> #include <algorithm> #include <cmath> #include <math.h> #include <set> #include <map> #include <unordered_set> #include <unordered_map> #include <vector> #include <stack> #include <queue> #include <deque> #include <bitset> #include <list> #include <iterator> #include <numeric> #include <complex> #include <tuple> #include <utility> #include <cassert> #include <assert.h> #include <climits> #include <limits.h> #include <ctime> #include <time.h> #include <random> #include <chrono> #include <fstream> using namespace std; // -------------------- Typedefs -------------------- // typedef long long ll; typedef unsigned long long ull; typedef double db; typedef long double ld; // -------------------- Defines -------------------- // #define pr pair #define mpr make_pair #define ff first #define ss second #define mset multiset #define mmap multimap #define uset unordered_set #define umap unordered_map #define umset unordered_multiset #define ummap unordered_multimap #define pqueue priority_queue #define sz(x) (int((x).size())) #define len(x) (int((x).length())) #define all(x) (x).begin(), (x).end() #define clr(x) (x).clear() #define ft front #define bk back #define pf push_front #define pb push_back #define popf pop_front #define popb pop_back #define lb lower_bound #define ub upper_bound #define bs binary_search // -------------------- Constants -------------------- // const int MAX = int(1e9 + 5); const ll MAXL = ll(1e18 + 5); const ll MOD = ll(1e9 + 7); const ll MOD2 = ll(998244353); // -------------------- Functions -------------------- // void fastio() { ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0); return; } void precision(int x) { cout << fixed << setprecision(x); return; } ll gcd0(ll a, ll b) { while (b) { a %= b; swap(a, b); } return a; } ll lcm0(ll a, ll b) { return a / gcd0(a, b) * b; } bool is_prime(ll a) { if (a == 1) return false; for (ll i = 2; i * i <= a; i++) if (a % i == 0) return false; return true; } bool is_square(ll a) { ll b = ll(sqrtl(ld(a))); return (b * b == a); } bool is_cube(ll a) { ll b = ll(cbrtl(ld(a))); return (b * b * b == a); } int digit_sum(ll a) { int sum = 0; while (a) { sum += int(a % 10); a /= 10; } return sum; } ll binpow(ll a, int b) { ll ans = 1; while (b) { if (b & 1) ans *= a; b >>= 1; a *= a; } return ans; } ll binpow_mod(ll a, ll b, ll mod) { ll ans = 1; while (b) { if (b & 1) ans = (ans * a) % mod; b >>= 1; a = (a * a) % mod; } return ans; } ll factorial(int a) { ll ans = 1; for (int i = 2; i <= a; i++) ans *= ll(i); return ans; } ll factorial_mod(int a, ll mod) { ll ans = 1; for (int i = 2; i <= a; i++) ans = (ans * ll(i)) % mod; return ans; } // -------------------- Solution -------------------- // const int N = 70005; vector<pr<int, int>> g[N]; int sz[N]; ll cnt[1005][1005]; ll ans[N]; int n, k; void dfs(int u, int p = 0) { int i, j; int v; for (i = 0; i < sz(g[u]); i++) { v = g[u][i].ff; if (v == p) continue; dfs(v, u); sz[u] += sz[v]; for (j = 0; j < g[u][i].ss; j++) cnt[u][k - g[u][i].ss] += cnt[v][j]; for (j = g[u][i].ss; j <= k; j++) cnt[u][j - g[u][i].ss] += cnt[v][j]; } sz[u]++; cnt[u][k]++; return; } void solve() { int i, j; cin >> n >> k; int u, v, l; for (i = 1; i < n; i++) { cin >> u >> v >> l; g[u + 1].pb(mpr(v + 1, l)); g[v + 1].pb(mpr(u + 1, l)); } /*dfs(2); for (i = 1; i <= n; i++) { for (j = 0; j <= k; j++) cout << cnt[i][j] << ' '; cout << "\n"; }*/ ll c; for (u = 1; u <= n; u++) { memset(sz, 0, sizeof(sz)); for (i = 1; i <= n; i++) memset(cnt[i], 0, sizeof(sz)); dfs(u); for (i = 0; i < sz(g[u]); i++) { v = g[u][i].ff; for (j = 0; j < g[u][i].ss; j++) cnt[u][k - g[u][i].ss] -= cnt[v][j]; for (j = g[u][i].ss; j <= k; j++) cnt[u][j - g[u][i].ss] -= cnt[v][j]; c = 0; for (j = 0; j < g[u][i].ss; j++) c += cnt[u][j]; ans[u] += c * ll(sz[v]); for (j = 0; j < g[u][i].ss; j++) cnt[u][k - g[u][i].ss] += cnt[v][j]; for (j = g[u][i].ss; j <= k; j++) cnt[u][j - g[u][i].ss] += cnt[v][j]; } } for (i = 1; i <= n; i++) cout << ans[i] << "\n"; return; } void precalc() { return; } int main() { fastio(); precalc(); int tests = 1, tc; //cin >> tests; for (tc = 1; tc <= tests; tc++) { solve(); } return 0; } /* # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # */
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