Submission #104502

#	Time	Username	Problem	Language	Result	Execution time	Memory
104502		E869120	Split the sequence (APIO14_sequence)	C++14	50 / 100	2054 ms	36344 KiB

sequence

#include <iostream>
#include <algorithm>
#include <vector>
using namespace std;

long long N, K, A1[100009], A2[100009], dp[10009][209], pre[10009][209];

long long ranged(int l, int r) {
	long long V1 = A1[r] - A1[l - 1]; V1 *= V1;
	long long V2 = A2[r] - A2[l - 1];
	return (V1 - V2) / 2;
}

long long solve() {
	for (int i = 0; i <= N; i++) {
		for (int j = 0; j <= K; j++) dp[i][j] = (1LL << 60);
	}
	dp[0][0] = 0;
	for (int i = 1; i <= N; i++) {
		for (int j = 1; j <= K; j++) {
			for (int k = 0; k < i; k++) {
				long long cost = dp[k][j - 1] + ranged(k + 1, i);
				if (dp[i][j] > cost) {
					dp[i][j] = cost; pre[i][j] = k;
				}
			}
		}
	}
	return dp[N][K];
}

int main() {
	cin >> N >> K; K++;
	for (int i = 1; i <= N; i++) { cin >> A1[i]; A2[i] = A1[i] * A1[i]; }
	for (int i = 1; i <= N; i++) { A1[i] += A1[i - 1]; A2[i] += A2[i - 1]; }
	cout << ranged(1, N) - solve() << endl;
	vector<int>T; int cx = N, cy = K;
	while (cy >= 1) {
		if (cy < K) T.push_back(cx);
		cx = pre[cx][cy]; cy--;
	}
	for (int i = T.size() - 1; i >= 0; i--) { cout << T[i]; if (i) cout << " "; }
	cout << endl;
	return 0;
}

• Subtask 1: 11 / 11
• Subtask 2: 11 / 11
• Subtask 3: 11 / 11
• Subtask 4: 17 / 17
• Subtask 5: 0 / 21
• Subtask 6: 0 / 29