Submission #1037474

#TimeUsernameProblemLanguageResultExecution timeMemory
1037474ef10Longest beautiful sequence (IZhO17_subsequence)C++17
0 / 100
3 ms5212 KiB
// Source: https://usaco.guide/general/io #include <bits/stdc++.h> using namespace std; int N; int A[100005]; int K[100005]; int BC[1<<10][1<<10]; pair<int,int> dp[1<<10][1<<10][25]; int prv[100005]; int main() { for (int i = 0; i < (1<<10); i++) { for (int j = 0; j < (1<<10); j++) { BC[i][j] = __builtin_popcount(i & j); } } cin >> N; for (int i = 0; i < N; i++) { cin >> A[i]; } for (int i = 0; i < N; i++) { cin >> K[i]; } iota(prv,prv+N,0); int longest = 0; int best = -1; for (int i = 0; i < N; i++) { int l = A[i] >> 10; int r = A[i] % (1<<10); int lbs = 1; for (int j = 0; j < (1<<10); j++) { int k = K[i]-BC[j][l]; if (k < 0 || k > 10) continue; if (dp[j][r][k].first + 1 > lbs) { lbs = dp[j][r][k].first + 1; prv[i] = dp[j][r][k].second; } } if (lbs > longest) { longest = lbs; best = i; } for (int j = 0; j < (1<<10); j++) { int k = BC[r][j]; if (k < 0 || k > 10) continue; if (lbs > dp[l][j][k].first) { dp[l][j][k].first = lbs; dp[l][j][k].second = i; } } } vector<int> res; for (int i = 0; i < longest; i++) { res.push_back(best); best = prv[best]; } reverse(res.begin(),res.end()); cout << longest << endl; for (auto e : res) { cout << e << " "; } }
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