Submission #1037416

#	Time	Username	Problem	Language	Result	Execution time	Memory
1037416		mindiyak	Boxes with souvenirs (IOI15_boxes)	C++14	100 / 100	394 ms	293972 KiB

boxes

#include "boxes.h"
#pragma GCC optimize("O1,O2,O3,Ofast,unroll-loops")
#include <bits/stdc++.h>
#include <string>
#include <iostream>
#include <cmath>
#include <numeric>
#include <limits>
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;
typedef pair<int, int> pi;
typedef pair<int, int> pl;
typedef pair<ld, ld> pd;
typedef vector<int> vi;
typedef vector<bool> vb;
typedef vector<vector<int>> vvi;
typedef vector<ld> vd;
typedef vector<ll> vl;
typedef vector<pi> vpi;
typedef vector<pl> vpl;
#define FOR(i, a, b) for (int i = a; i < (b); i++)
#define F0R(i, a) for (int i = 0; i < (a); i++)
#define FORd(i, a, b) for (int i = (b)-1; i >= a; i--)
#define F0Rd(i, a) for (int i = (a)-1; i >= 0; i--)
#define trav(a, x) for (auto &a : x)
#define uid(a, b) uniform_int_distribution<int>(a, b)(rng)
#define len(x) (int)(x).size()
#define mp make_pair
#define pb push_back
#define F first
#define nl endl
#define S second
#define lb lower_bound
#define ub upper_bound
#define aint(x) x.begin(), x.end()
#define raint(x) x.rbegin(), x.rend()
#define ins insert
const int MOD = 1000000007;

int L;
vl arr(1e7+10,0);
vl arr_sum(1e7+10,0);

ll dis(ll a,ll b){
    return min(abs(b-a),L-abs(b-a));
}

ll dis2(ll a,ll b){
    // return min(abs(b-a),dis(0,a)+dis(0,b));
    return abs(b-a);
}

long long delivery(int N, int K, int m, int p[]) {
    L = m;
    FOR(i,0,N){
        arr[i] = dis(p[i],0);
    }

    FOR(i,1,N)
        arr_sum[i] = dis(p[i],p[i-1]) + arr_sum[i-1];

    ll ans = LLONG_MAX;

    FOR(j,0,K+1){
        ll temp = 0;
        int last = 0;

        if(j != 0){
            // cout << "A " << arr[0] << " " << arr[j-1] << " " << dis2(p[0],p[j-1]) << endl;
            temp += arr[0] + arr[j-1];
            if(j != 1){
                temp += arr_sum[j-1] - arr_sum[0];
            }
            // FOR(l,0,j-1)
            //     temp += dis(p[l],p[l+1]);
        }

        for(int i=j;i<N;i+=K){
            if(i+K-1 > N-1)break;
            last = i+K;
            // cout << "B " << arr[i] << " " << arr[i+K-1] << " " << dis2(p[i],p[i+K-1]) << endl;
            temp += arr[i] + arr[i+K-1] + arr_sum[i+K-1] - arr_sum[i];
            // FOR(l,i,i+K-1)
            //     temp += dis(p[l],p[l+1]);
        }

        if(last <= N-1){
            // cout << "C " << arr[N-1] << " " << arr[last] << " " << dis2(p[last],p[N-1]) << endl;
            temp += arr[N-1] + arr[last] + arr_sum[N-1] - arr_sum[last];
            // FOR(l,last,N-1)
            //     temp += dis(p[l],p[l+1]);
        }

        // cout << j << " " << temp << endl;
        ans = min(ans,temp);
        }

    return ans;
}

• Subtask 1: 10 / 10
• Subtask 2: 10 / 10
• Subtask 3: 15 / 15
• Subtask 4: 15 / 15
• Subtask 5: 20 / 20
• Subtask 6: 30 / 30