Submission #1035920

#TimeUsernameProblemLanguageResultExecution timeMemory
1035920AmirAli_H1Aliens (IOI16_aliens)C++17
4 / 100
34 ms48804 KiB
// In the name of Allah #include <bits/stdc++.h> #include "aliens.h" using namespace std; typedef long long int ll; typedef long double ld; typedef pair<int, int> pii; typedef pair<ll, ll> pll; typedef complex<ld> cld; #define all(x) (x).begin(),(x).end() #define len(x) ((ll) (x).size()) #define F first #define S second #define pb push_back #define sep ' ' #define endl '\n' #define Mp make_pair #define kill(x) cout << x << '\n', exit(0) #define set_dec(x) cout << fixed << setprecision(x); #define file_io(x,y) freopen(x, "r", stdin); freopen(y, "w", stdout); mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); const int maxn = 1e5 + 4; const int maxs = 2e6 + 4; const ll oo = 5e12 + 4; int n, m, k; pii a[maxn]; vector<pii> A; vector<int> ls[maxs]; priority_queue<pair<int, pii>> qu; pll dp[maxn]; ll cal(pll a, pll b) { ll d = max(0ll, (a.F + a.S) - (b.F - b.S)); return (4 * b.S * b.S - d * d); } pll get_val(int i, int j, ll R) { ll x1 = A[i + 1].F - A[i + 1].S, x2 = A[j].F + A[j].S; ll d = (x1 - x2) / 2; pll x = Mp(x1 + d, d); return Mp(dp[i].F + cal(A[i], x) + R, dp[i].S + 1); } pll get_res(ll R) { dp[0] = Mp(0, 0); for (int i = 1; i < n; i++) { dp[i] = get_val(0, i, R); for (int j = 1; j < i; j++) dp[i] = min(dp[i], get_val(j, i, R)); } return dp[n - 1]; } ll take_photos(int Nx, int Mx, int Kx, vector<int> rx, vector<int> cx) { n = Nx; m = Mx; k = Kx; for (int i = 0; i < n; i++) { if (cx[i] > rx[i]) swap(cx[i], rx[i]); a[i] = Mp(rx[i], cx[i]); ls[a[i].F].pb(i); } A.pb(Mp(0, 0)); for (int i = m - 1; i >= 0; i--) { for (int j : ls[i]) { qu.push(Mp(-a[j].S, Mp(i, j))); } for (int j : ls[i]) { if (qu.top().S.S == j) { int x1 = a[j].F, y1 = a[j].S; A.pb(Mp(x1 + y1 + 1, x1 - y1 + 1)); } } } n = len(A); sort(all(A)); ll l = -oo, r = oo; while (r - l > 1) { ll mid = (l + r) / 2; if (get_res(mid).S > k) l = mid; else r = mid; } pll R = get_res(r); ll ans = R.F - R.S * r; return ans / 4; }
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