Submission #1034190

#TimeUsernameProblemLanguageResultExecution timeMemory
1034190Zero_OPCyberland (APIO23_cyberland)C++17
20 / 100
517 ms38224 KiB
#include<bits/stdc++.h> #ifndef HOME #include "cyberland.h" //including problem's library #endif //HOME using namespace std; #define left __left #define right __right #define next __next #define prev __prev #define div __div #define pb push_back #define pf push_front #define all(v) v.begin(), v.end() #define sz(v) (int)v.size() #define compact(v) v.erase(unique(all(v)), end(v)) #define dbg(v) "[" #v " = " << (v) << "]" #define file(name) if(fopen(name".inp", "r")) {freopen(name".inp", "r", stdin); freopen(name".out", "w", stdout); } template<typename T> bool minimize(T& a, const T& b){ if(a > b) return a = b, true; return false; } template<typename T> bool maximize(T& a, const T& b){ if(a < b) return a = b, true; return false; } template<int dimension, typename T> struct vec : public vector<vec<dimension - 1, T>> { static_assert(dimension > 0, "Dimension must be positive !\n"); template<typename... Args> vec(int n = 0, Args... args) : vector<vec<dimension - 1, T>> (n, vec<dimension - 1, T>(args...)) {} }; template<typename T> struct vec<1, T> : public vector<T> { vec(int n = 0, T val = T()) : vector<T>(n, val) {} }; double solve(int N, int M, int K, int H, vector<int> x, vector<int> y, vector<int> c, vector<int> arr){ vector<vector<pair<int, int>>> adj(N); for(int i = 0; i < M; ++i){ int u = x[i], v = y[i], w = c[i]; adj[u].push_back({v, w}); adj[v].push_back({u, w}); } K = min(K, 70); using node = tuple<double, int, int>; const double inf = 1e18; priority_queue<node, vector<node>, greater<node>> pq; vector<vector<double>> d(71, vector<double>(N, inf)); d[0][0] = 0; pq.push({d[0][0], 0, 0}); while(!pq.empty()){ double tots; int u, k; tie(tots, u, k) = pq.top(); pq.pop(); if(d[k][u] != tots) continue; if(u == H) return tots; for(auto [v, w] : adj[u]){ if(arr[v] == 0 && d[k][v] > 0){ //apply operation 1 d[k][v] = 0; pq.push({d[k][v], v, k}); } if(d[k][v] > d[k][u] + w){ //not apply any operations d[k][v] = d[k][u] + w; pq.push({d[k][v], v, k}); } if(k < K && arr[v] == 2 && d[k + 1][v] > (d[k][u] + w) / 2.0){ //apply operation 2 d[k + 1][v] = (d[k][u] + w) / 2.0; pq.push({d[k + 1][v], v, k + 1}); } } } return -1; } #ifdef HOME int main(){ ios_base::sync_with_stdio(0); cin.tie(0); cout << solve(3, 2, 30, 2, {1, 2}, {2, 0}, {12, 4}, {1, 2, 1}) << '\n'; cout << solve(4, 4, 30, 3, {0, 0, 1, 2}, {1, 2, 3, 3}, {5, 4, 2, 4}, {1, 0, 2, 1}) << '\n'; return 0; } #endif // HOME
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