Submission #1032389

#	Time	Username	Problem	Language	Result	Execution time	Memory
1032389		0pt1mus23	Holding (COCI20_holding)	C++14	55 / 110	31 ms	49492 KiB

holding

#pragma GCC optimize("O3", "inline")
#define skillissue <bits/stdc++.h>
#define ultra_mal std
#include skillissue
using namespace ultra_mal;
 
mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());
#define ins insert
#define pb push_back
#define int long long int
#define pii pair<int, int>
#define endl '\n' 
#define drop(x) cout<<(x)<<endl; return;
#define all(x) x.begin(),x.end()
#define hash FhashF
const int mod = 1e9 +7, sze = 1e4 +10, inf = LLONG_MAX, P = 1453;
// const int L = 30;

int dp[111][111][sze];
int dp2[111][111][sze];
void optimus(){
    int n,l,r,k;
    cin>>n>>l>>r>>k;
    vector<int> arr(n+1);
    for(int i=1;i<=n;i++){
        cin>>arr[i];
    }
    int sum=0;
    for(int i = l;i<=r;i++){
        sum+=arr[i];
    }

    for(int i =1;i<l;i++){
        for(int j= l;j<=r;j++){
            for(int p=0;p<=k;p++){
                
                dp[i][j][p]= max({ 
                    dp[i-1][j][p],
                    dp[i][j-1][p],
                    (int)0
                });
                if((j-i)<=p){
                    dp[i][j][p]=max(dp[i][j][p],dp[i-1][j-1][p - (j-i)] + arr[j]-arr[i]);
                }
                // cout<<i<<" "<<j<<" "<<p<<" "<<dp[i][j][p]<<" "<<
                //     dp[i-1][j-1][p - (j-i)]+  arr[i]- arr[j]<<endl;
            }
        }
    }
    /*
        r+1- >n
        l->r
    */
    for(int i =r;i>=l;i--){
        
        for(int j=r+1;j<=n;j++){
            for(int p=0;p<=k;p++){
                dp2[i][j][p] = max(dp2[i][j][p], dp2[i + 1][j][p]);
                dp2[i][j][p] = max(dp2[i][j][p], dp2[i][j - 1][p]);
                if(k >= (j-i)){
                    dp2[i][j][p] = max(dp2[i][j][p], dp2[i + 1][j - 1][k - (j-i)] + arr[i] - arr[j]);
                }
            }
        }
    }
    int mx =0 ;
    for(int i = l-1;i<=r;i++){
        for(int j=0;j<=k;j++){
            mx=max(mx, dp[l-1][i][j] + dp2[i+1][n][k - j]);
        }
    }
    drop(sum - mx);
}
 
signed main() {
    cin.tie(0)->sync_with_stdio(0);
    int tt = 1;
    // cin>>tt;
    while(tt--){
        optimus();
    }
 
    return 0;
} 
 

• Subtask 1: 22 / 22
• Subtask 2: 33 / 33
• Subtask 3: 0 / 33
• Subtask 4: 0 / 22