Submission #1030004

#TimeUsernameProblemLanguageResultExecution timeMemory
1030004mindiyakClosing Time (IOI23_closing)C++17
0 / 100
264 ms49372 KiB
#include "closing.h" #pragma GCC optimize("O1,O2,O3,Ofast,unroll-loops") #include <bits/stdc++.h> #include <string> #include <iostream> #include <cmath> #include <numeric> using namespace std; typedef long long ll; typedef unsigned long long ull; typedef long double ld; typedef pair<int, int> pi; typedef pair<int, int> pl; typedef pair<ld, ld> pd; typedef vector<int> vi; typedef vector<bool> vb; typedef vector<vector<int>> vvi; typedef vector<vector<ll>> vvl; typedef vector<ld> vd; typedef vector<ll> vl; typedef vector<pi> vpi; typedef vector<pl> vpl; #define FOR(i, a, b) for (int i = a; i < (b); i++) #define F0R(i, a) for (int i = 0; i < (a); i++) #define FORd(i, a, b) for (int i = (b)-1; i >= a; i--) #define F0Rd(i, a) for (int i = (a)-1; i >= 0; i--) #define trav(a, x) for (auto &a : x) #define uid(a, b) uniform_int_distribution<int>(a, b)(rng) #define len(x) (int)(x).size() #define mp make_pair #define pb push_back #define F first #define nl endl #define S second #define lb lower_bound #define ub upper_bound #define aint(x) x.begin(), x.end() #define raint(x) x.rbegin(), x.rend() #define ins insert const int MOD = 1000000007; priority_queue<pair<ll,int>> arr; vector<vpi> paths(2e5+5); vector<priority_queue<ll>> costs(2e5+5, priority_queue<ll>()); vi costindex(2e5+5,0); void dfs(int pos,int cost,int prev){ for(pi edge:paths[pos]){ if(edge.F == prev)continue; // cout << pos << " " << edge.F << " " << edge.S << " " << cost << " " << isX << endl; costs[edge.F].push(-(edge.S+cost)); dfs(edge.F,edge.S+cost,pos); } } int max_score(int N, int X, int Y, ll K,vi U, vi V, vi W) { arr = priority_queue<pair<ll,int>>(); paths = vector<vpi>(2e5+5); costs = vector<priority_queue<ll>>(2e5+5, priority_queue<ll>()); costindex = vi(2e5+5,0); FOR(i,0,N-1){ paths[U[i]].pb({V[i],W[i]}); paths[V[i]].pb({U[i],W[i]}); } // vi visited(2e5+5); dfs(X,0,-1); dfs(Y,0,-1); int ans = 2; FOR(i,0,N){ if(!costs[i].empty()){ arr.push({costs[i].top(),i}); costs[i].pop(); } } while(K > 0){ if(arr.empty())break; pair<ll,int> node = arr.top();arr.pop(); ll a = -node.F; int pos = node.S; if(!costs[pos].empty()){ ll diffcost = -costs[pos].top()-a; costs[pos].pop(); arr.push({-diffcost,pos}); } // cout << K << " " << a << " " << pos << endl; if(K >= a){ K-=a; ans++; }else{ break; } } return ans; }
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