Submission #1028855

#TimeUsernameProblemLanguageResultExecution timeMemory
1028855underwaterkillerwhaleRemittance (JOI19_remittance)C++17
0 / 100
1 ms472 KiB
#include <bits/stdc++.h> #define se second #define fs first #define mp make_pair #define pb push_back #define ll long long #define ii pair<ll,ll> #define ld long double #define SZ(v) (int)v.size() #define ALL(v) v.begin(), v.end() #define bit(msk, i) ((msk >> i) & 1) #define iter(id, v) for(auto id : v) #define rep(i,m,n) for(int i=(m); i<=(n); i++) #define reb(i,m,n) for(int i=(m); i>=(n); i--) using namespace std; mt19937_64 rd(chrono :: steady_clock :: now().time_since_epoch().count()); ll Rand(ll l, ll r) { return uniform_int_distribution<ll> (l, r)(rd); } const int N = 2e5 + 7; const int Mod = 1e9 + 7; const int szBL = 320; const int INF = 1e9; const int BASE = 1337; int n; pair<int,int> a[N]; void solution () { cin >> n; // n = 1e5; // rep (i, 1, n) a[i].fs = Rand(1, 1e5), a[i].se = Rand(1, 1e5); rep (i, 1, n) cin >> a[i].fs >> a[i].se; while (1) { rep (i, 1, n) { if (a[i].fs > a[i].se + 1) { int pos = i; while (a[pos].fs > a[pos].se + 1) { int nxt = 1 + pos % n; // cout << pos <<": "<<a[pos].fs<<"->"<<a[pos].fs -(a[pos].fs - a[pos].se) / 2 * 2 <<"\n"; a[nxt].fs += (a[pos].fs - a[pos].se) / 2; a[pos].fs -= (a[pos].fs - a[pos].se) / 2 * 2; pos = nxt; } } // rep (j, 1, n) cout << a[j].fs<< " "; cout<<"\n"; } int ok = 1; rep (i, 1, n) if (a[i].fs > a[i].se + 1) { ok = 0; } if (ok) break; } int edcase = 1; rep (i, 1, n) { if (a[i].fs != a[i].se + 1 || a[i].se == 0) edcase = 0; } if (edcase ) { cout <<"Yes\n"; return; } rep (i, 1, n) if (a[i].fs != a[i].se) { cout <<"No\n"; return; } cout <<"Yes\n"; } #define file(name) freopen(name".inp", "r", stdin); \ freopen(name".out", "w", stdout); int main () { // file("c"); ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); ll num_Test = 1; // cin >> num_Test; while(num_Test--) solution(); } /* nếu mình nghĩ sẽ thay đổi định nghĩa, kiểu dữ liệu của hàm hay mảng j thì mình phải nghĩ xem nó sẽ ảnh hưởng đến các phần nào 0 0 1 0 0 0 */
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