Submission #1027686

#TimeUsernameProblemLanguageResultExecution timeMemory
1027686caterpillowMarriage questions (IZhO14_marriage)C++17
66 / 100
150 ms4180 KiB
#include <bits/stdc++.h> using namespace std; using db = long double; using ll = long long; using pl = pair<ll, ll>; using pi = pair<int, int>; #define vt vector #define f first #define s second #define pb push_back #define all(x) x.begin(), x.end() #define size(x) ((int) (x).size()) #define FOR(i, a, b) for (int i = (a); i < (b); i++) #define ROF(i, a, b) for (int i = (b) - 1; i >= (a); i--) #define F0R(i, b) FOR (i, 0, b) #define endl '\n' const ll INF = 1e18; const int inf = 1e9; template<typename Tuple, size_t... Is> void print_tuple(const Tuple& t, index_sequence<Is...>) { ((cerr << (Is == 0 ? "{" : ", ") << get<Is>(t)), ...); cerr << "}"; } template<typename... Args> ostream& operator<<(ostream& os, const tuple<Args...>& t) { print_tuple(t, index_sequence_for<Args...>{}); return os; } ostream& operator<<(ostream& os, string& s) { for (char c : s) os << c; return os; } template<template<typename> class Container, typename T> ostream& operator<<(ostream& os, Container<T> o) { os << "{"; int g = size(o); for (auto i : o) os << i << ((--g) == 0 ? "" : ", "); os << "}"; return os; } template<typename T, typename V> ostream& operator<<(ostream& os, const pair<T, V> p) { os << "{" << p.f << ", " << p.s << "}"; return os; } template <typename T, typename... V> void printer(const char *names, T &&head, V &&...tail) { int i = 0; while (names[i] != '\0' && names[i] != ',') i++; constexpr bool is_str = is_same_v<decay_t<T>, const char*>; if constexpr (is_str) cerr << head; // ignore directly passed strings else cerr.write(names, i) << " = " << head; if constexpr (sizeof...(tail)) cerr << (is_str ? "" : ","), printer(names + i + 1, tail...); else cerr << endl; } #ifdef LOCAL #define dbg(...) std::cerr << __LINE__ << ": ", printer(#__VA_ARGS__, __VA_ARGS__) #else #define dbg(x...) #define cerr if (0) std::cerr #endif /* range perfect matching goes crazy since kuhn's is more efficient when lhs is small, we need the girls to be on the left we want to find the maximum r for each l, and two pointer it */ int n, m, k; // n is lhs (girls), m is rhs (boys) vt<vt<int>> adj; // l -> r vt<int> mni; // index of first neighbour we iterate over vt<int> mate; // mate = rhs -> lhs bool seen[2001]; // seen of lhs bool dfs(int u) { if (seen[u]) return false; seen[u] = true; FOR (i, mni[u], size(adj[u])) { int v = adj[u][i]; if (mate[v] == -1 || dfs(mate[v])) { mate[v] = u; return true; } } return false; } main() { cin.tie(0)->sync_with_stdio(0); cin >> m >> n >> k; adj.resize(n); mni.resize(m); mate.resize(m, -1); vt<pi> edges; vt<vt<int>> radj(m); F0R (i, k) { int u, v; cin >> u >> v; u--, v--; // u is boy, v is girl radj[u].pb(v); } int r = 0, matches = 0; vt<int> mxr(m, m + 1); // exc queue<int> to_match; F0R (i, n) to_match.push(i); F0R (l, m) { cerr << endl; while (size(to_match)) { if (r == m) break; // add these edges for (int u : radj[r]) adj[u].pb(r); // try augment int u = to_match.front(); memset(seen, 0, sizeof(seen)); while (dfs(u)) { to_match.pop(); if (!size(to_match)) break; u = to_match.front(); } r++; } if (size(to_match)) break; mxr[l] = r; // remove edges for (int u : radj[l]) { mni[u]++; } // check if we unmatched someone if (mate[l] != -1) { to_match.push(mate[l]); mate[l] = -1; } } ll ans = 0; F0R (i, m) ans += m - mxr[i] + 1; cout << ans << endl; }

Compilation message (stderr)

marriage.cpp:102:1: warning: ISO C++ forbids declaration of 'main' with no type [-Wreturn-type]
  102 | main() {
      | ^~~~
marriage.cpp: In function 'int main()':
marriage.cpp:118:16: warning: unused variable 'matches' [-Wunused-variable]
  118 |     int r = 0, matches = 0;
      |                ^~~~~~~
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