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Submission #102609

#TimeUsernameProblemLanguageResultExecution timeMemory
102609faustaadpMeetings (IOI18_meetings)C++17
36 / 100
1045 ms7908 KiB
#include "meetings.h" #include <bits/stdc++.h> #define pb push_back #define mp make_pair #define fi first #define se second typedef long long ll; using namespace std; ll n,i,a[101010],ST[404040],ki[101010],ka[101010],P[5050],S[5050]; void upd(ll aa,ll bb,ll cc,ll dd,ll ee) { if(aa==bb)ST[ee]=dd; else { ll ce=(aa+bb)/2; if(cc<=ce)upd(aa,ce,cc,dd,ee*2); else upd(ce+1,bb,cc,dd,ee*2+1); ST[ee]=max(ST[ee*2],ST[ee*2+1]); } } ll que(ll aa,ll bb,ll cc,ll dd,ll ee) { if(bb<cc||dd<aa)return 0; else if(cc<=aa&&bb<=dd)return ST[ee]; else { ll ce=(aa+bb)/2; return max(que(aa,ce,cc,dd,ee*2),que(ce+1,bb,cc,dd,ee*2+1)); } } std::vector<long long> minimum_costs(std::vector<int> H, std::vector<int> L,std::vector<int> R) { n=H.size(); for(i=1;i<=n;i++)a[i]=H[i-1]; for(i=1;i<=n;i++) if(a[i]==a[i-1]) ki[i]=ki[i-1]; else ki[i]=i; for(i=n;i>=1;i--) if(a[i]==a[i+1]) ka[i]=ka[i+1]; else ka[i]=i; for(i=1;i<=n;i++) if(a[i]==1) upd(1,n,i,ka[i]-ki[i]+1,1); int Q = L.size(); std::vector<long long> C(Q); for (int j = 0; j < Q; ++j) { L[j]++; R[j]++; if(Q<=5000&&n<=5000) { C[j]=1e18; { stack<pair<ll,ll> > st; P[L[j]-1]=0; for(i=L[j];i<=R[j];i++) { P[i]=P[i-1]+a[i]; ll las=i; while(!st.empty()&&st.top().fi<=a[i]) { P[i]-=(las-st.top().se)*st.top().fi; P[i]+=(las-st.top().se)*a[i]; las=st.top().se; st.pop(); } st.push(mp(a[i],las)); } } { stack<pair<ll,ll> > st; S[R[j]+1]=0; for(i=R[j];i>=L[j];i--) { S[i]=S[i+1]+a[i]; ll las=i; while(!st.empty()&&st.top().fi<=a[i]) { //cout<<"_"<<i<<"\n"; S[i]-=(st.top().se-las)*st.top().fi; S[i]+=(st.top().se-las)*a[i]; las=st.top().se; st.pop(); } st.push(mp(a[i],las)); //cout<<i<<" "<<S[i]<<"\n"; } } for(i=L[j];i<=R[j];i++) C[j]=min(C[j],P[i]+S[i]-a[i]); continue; } //cout<<ka[L[j]]<<" "<<ki[R[j]]<<"\n"; C[j]=que(1,n,ka[L[j]]+1,ki[R[j]]-1,1); //cout<<C[j]<<"_\n"; if(a[R[j]]==1&&ki[R[j]]>=L[j])C[j]=max(C[j],R[j]-ki[R[j]]+1); else if(a[R[j]]==1)C[j]=max(C[j],R[j]-L[j]+1LL); if(a[L[j]]==1&&ka[L[j]]<=R[j])C[j]=max(C[j],ka[L[j]]-L[j]+1); else if(a[L[j]]==1)C[j]=max(C[j],R[j]-L[j]+1LL); C[j]=2*(R[j]-L[j]+1)-C[j]; } return C; }
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