Submission #1023129

#	Time	Username	Problem	Language	Result	Execution time	Memory
1023129		thinknoexit	Overtaking (IOI23_overtaking)	C++17	0 / 100	3544 ms	133804 KiB

overtaking

#include "overtaking.h"
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
const int N = 1010;
struct A {
    ll t, s;
    int idx;
    bool operator < (const A& o) const {
        return t < o.t;
    }
} a[N][N];
ll pref[N][N], s[N];
vector<pair<ll, ll>> event;
int n, m;
ll X;
ll cal_arrival_time(ll Y) {
    ll now = Y;
    for (int i = 0;i < m - 1;i++) {
        ll mx = now + X * (s[i + 1] - s[i]);
        {
            int l = -1, r = n - 1;
            while (l < r) {
                int mid = (l + r + 1) >> 1;
                if (a[i][mid].t < now) l = mid;
                else r = mid - 1;
            }
            if (l != -1) mx = max(mx, pref[i][l]);
        }
        now = mx;
    }
    return now;
}
void init(int L, int NN, vector<ll> T, vector<int> W, int X, int M, vector<int> S) {
    n = NN;
    m = M;
    ::X = X;
    for (int i = 0;i < m;i++) {
        s[i] = S[i];
    }
    for (int i = 0;i < n;i++) {
        a[0][i] = { T[i], W[i], i };
    }
    for (int K = 0;K < m - 1;K++) {
        sort(a[K], a[K] + n);
        int idx = 0;
        ll mx = 0;
        for (int i = 0, j;i < n;i = j) {
            for (j = i;j < n && a[K][i].t == a[K][j].t;j++) {
                a[K + 1][idx++] = { max(a[K][j].t + a[K][j].s * (s[K + 1] - s[K]), mx)
                                    , a[K][j].s, a[K][j].idx };
            }
            for (j = i;j < n && a[K][i].t == a[K][j].t;j++) {
                mx = max(mx, a[K][j].t + a[K][j].s * (s[K + 1] - s[K]));
            }
            for (j = i;j < n && a[K][i].t == a[K][j].t;j++) {
                pref[K][j] = mx;
            }
        }
    }
    sort(a[m - 1], a[m - 1] + n);
    ll INF = a[m - 1][n - 1].t;
    ll cur = cal_arrival_time(0);
    event.push_back({ 0, cur });
    ll now = 0;
    while (now <= INF) {
        ll l = now + 1, r = INF + 1;
        while (l < r) {
            ll mid = (l + r) / 2;
            if (cal_arrival_time(mid) - mid != cur - now) r = mid;
            else l = mid + 1;
        }
        now = l;
        cur = cal_arrival_time(now);
        event.push_back({ now, cur });
    }
}
ll arrival_time(ll Y) {
    int idx = lower_bound(event.begin(), event.end(), pair<ll, ll>(Y + 1, 0ll)) - event.begin() - 1;
    return event[idx].second + (Y - event[idx].first);
}

• Subtask 0: 0 / 0
• Subtask 1: 0 / 9
• Subtask 2: 0 / 10
• Subtask 3: 0 / 20
• Subtask 4: 0 / 26
• Subtask 5: 0 / 35